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lubasha [3.4K]
3 years ago
15

Here is a train table: Newport: 04:58. 13:32 Shrewsbury: 07:22 A) How long is the journey from Newport to Shrewsbury if you catc

h the 04:58 train? B) The 13:32 train from Newport takes 2 hours and 29 minutes to get to Shrewsbury. What is the missing time?
Mathematics
1 answer:
ehidna [41]3 years ago
6 0

Answer:b

Step-by-step explanation:

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24 square feet is the answer
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Whats the simpilest form of the ratio <br>48 min to 3 hours.​
MArishka [77]

15:4.

Step-by-step explanation:

1 hour = 60 min

3 hours = 60 x 3 = 180 min

Ratio:

180/48

Simplest form 15/4

Therefore, the simplest form of the ratio will be 15:4

7 0
3 years ago
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Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
Divide. Write the quotient in lowest terms. 4\dfrac{2}{3} \div 7 =4 3 2 ​ ÷7=4, start fraction, 2, divided by, 3, end fraction,
velikii [3]

Answer:

\dfrac{2}{3}

Step-by-step explanation:

Given the quotient: 4\dfrac{2}{3} \div 7

Step 1: Write 4\dfrac{2}{3} in improper fraction.

4\dfrac{2}{3}=\dfrac{14}{3}

Therefore:

4\dfrac{2}{3} \div 7=\dfrac{14}{3} \div 7

<u>Step 2:</u> Change the division sign to multiplication by taking the reciprocal of 7

\dfrac{14}{3} \div 7 =\dfrac{14}{3} X\dfrac{1}{7} \\$Simplify\\\\=\dfrac{2}{3}

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3 years ago
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