Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
For the first picture using Pythagorean Theorem, we know that a^2 + b ^2 = c^2 but since we only know c ( 99.2) and b ( 62 ) we need to use the theorem to find a the equation we use for that is :
A = square root of ( c^2 - B^2 )
A = 77.44
She bought 2 1/4 more blue ribbon.
4 3/8 - 2 1/8 = 2.25
2.25= 9/4
9/4= 2 1/4
-Katie ;)
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