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4 years ago

What's the numerator for the following rational expression? x/y+ 7/y = ?/y

Mathematics

1 answer:

Mice21 [21]4 years ago

7 0

Answer:

x+7

Step-by-step explanation:

7/y-?/y=x/y

?=x+7

Sorry, I wish I could elaborate more but I can't...

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Review #3 (TYPE ANSWERS HERE)

alexdok [17]

The correct answer would be - Orange 4 times

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3 years ago

Student tickets cost $6.25 each at a local movie theater. Which proportion could be used to find the number of student tickets,

leva [86]

Answer:a

Step-by-step explanation:all the other ones are not smart

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3 years ago

SURFACE AREAS - PYRAMIDS?

Bond [772]

The total surface area consists of the base area and the surface area (the area of all lateral faces). The base is a hexagon with side a=3 cm.

$A_{hexagon}=6A_{triangle}=6\cdot \dfrac{1}{2} \cdot \dfrac{a^2\sqrt{3}}{4} =\dfrac{3}{4} \cdot 3^2\cdot \sqrt{3}=\dfrac{27\sqrt{3}}{4}$ sq. cm.

Each lateral face is an isosceles triangle with height h=12 cm and base a=3 cm. The area of one such lateral triangle is

$A_{lateral}=\dfrac{1}{2}\cdot h\cdot a= \dfrac{1}{2}\cdot 12\cdot 3=18$ sq. cm.

Then the total surface area is:

$A_{total}= \dfrac{27\sqrt{3}}{4} +6\cdot 18=\dfrac{27\sqrt{3}}{4} +108=11.7+108=119.7$ sq. cm.

Answer: 119.7 sq. cm.

7 0

4 years ago

t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.

kondaur [170]

Answer:

a) $t = 1$ , b) $t = -2$ , c) Concave upward: $(-\infty, 1)$ . No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

$f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}$

By factorizing each component, the function is re-arranged as:

$f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}$

There is no avoidable discontinuities. The only point where tangent line is vertical is $t = 1$ .

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is horizontal is $t = -2$ .

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

$f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}$

$f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]$

$f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}$

$f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}$

The only critical point is:

$-6\cdot (t+2) = 0$

$t = -2$ (which coincides with the result of point b)

$f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]$

$f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}} \right]$

The value associated with the critical point is:

$f''(-2) = \frac{2}{9}$

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is $(-\infty, 1)$ . There is no absolute maximums and, therefore, there is no interval that is concave downward.

7 0

4 years ago

The sum of two consecutive odd integers is 156. Which is an equation that can be used to solve for x? Please

OLEGan [10]

Answer:

x+(x+2) = 156

Step-by-step explanation:

Let x = 1st odd integer

x+2 = next odd integer

x+(x+2) = 156

2x+2 =156

Subtract 2

2x= 154

Divide by 2

x = 77

x+2 = 79

4 0

4 years ago