Answer:
the average distance from the mean is 84.8
Step-by-step explanation:
The computation of the average distance from the mean is shown below;
= Total sum ÷ number of observations
= (80 + 76 + 88 + 96+ 75 + 83 + 68 + 94 + 99 + 89) ÷ (10)
= 848 ÷ 10
= 84.8
Hence, the average distance from the mean is 84.8
-3x + 10 = 34
Subtract 10 from both sides:
-3x = 24
Divide both sides by -3:
X = 24 / -3
X = -8
musiclover10045
Middle School Mathematics 39+20 pts
I have two questions to solve
-3x+10=34
13x-4=11x+10-8
Combine like terms on the right side:
13x -4 = 11x + 2
Subtract 11x from both sides:
2x -4 = 2
Add 4 to both sides:
2x = 6
Divide both sides by 2:
X = 6/2
X = 3
Answer:
3/8÷1/4=1 1/2
Step-by-step explanation:
I am not sure what you are asking here, So I am gonna explain how you divide this.
So using the KCF method (Keep Change Flip) You would KEEP the first fraction (3/8) and CHANGE the operation (from divide to multiply) then FLIP your second fraction (1/4 to 4/1)
After doing this, it should look like:
3 4
x
8 1
Now that we got that, you multiply from left to right. 3×4 is 12. 8×1=8.
That should leave you with 12/8. But this is an improper fraction. So you would divide top by bottom to get a mixed fraction.
It should look like this
01. 1 1/2
8 12
8
4
Step by step explanation:
8 only goes into 12 one time. So you would subtract 12 by 8, and get 4. From that you would get 1 4/8 but 1 4/8 can be simplified to 1 1/2.
So it is 1 1/2
Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
