So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.
Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4
So then we get 8x^4/(x^(3/4)+7x)^4
8x^4/(x^(3/4)+7x)^4
Answer:
g
Step-by-step explanation:
b
range: {6, 1, -1}
y = 4-x
when x = -2, y = 6
when x = 3, y = 1
when x = 5, y = -1
