Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
Answer:
This one ↓↓↓↓↓↓
Step-by-step explanation:
The picture attached is the reflection over the line y = 0
-Chetan K
5% of £42 = £2.10
10% of £42 = £4.20
15% of £42 = £6.30
£42 - £6.30 = £35.70
£50 - £35.70 = £14.30
the answer is £14.30
solution is first os all find median
median is( 45+61)/2=53
find median of no in left of 53
it is 37
find median of no in right of 53
it is 64
now interquartile range=64-53=27