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3 years ago

In triangle ABC, m is the value of x?

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

6 0

Answer:

lol if a = 90 then b = 75 so C is 105

then you get the derivative number which is X by adding a2 b2 then dividing by the c2. so its true

Step-by-step explanation:

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The perimeter of a parallelogram is 180 cm. One side exceeds the other by 10 cm. What are the lengths of adjacent sides of the p

Georgia [21]

Answer:

one side is 40 other is 50

Step-by-step explanation:

perimeter=180cm

let one side=length=x

Acc. to condition:

other side=width=x+10 (one side exceed other by 10)

perimeter= 2(length+width)

subtitue all values given above:

180=2(x+x+10)

180=2(2x+10)

2x+10=180/2

2x+10=90

2x=90-10

2x=80

x=40

now

lenght=x=40cm

width=x+10=40+10

width=50cm

8 0

3 years ago

Do fractions n always need to be renamed to the largest unit?

BabaBlast [244]

No, but if it's an improper fraction it should be done

5 0

3 years ago

Write the following proportion using colons. 7 is to 21 as 3 is to 9.

Lubov Fominskaja [6]

The answer is 7:21 = 3:9.

7 0

3 years ago

Read 2 more answers

Which of the following represents the range of the graph below?

MaRussiya [10]

Answer:

y ≤0

Step-by-step explanation:

The range is the values that y can take

We see that y can be less than or equal to 0

y ≤0

8 0

3 years ago

Write the standard form equation of the ellipse shown in the graph, and identify the foci.

vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3) and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1$

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6 and b = 4

The standard equation becomes

$\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1$

$\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1$

Foci are (h,k+c) and (h,k-c)

$c=\sqrt{a^2-b^2}$

Plug in the a=6 and b=4

$c=\sqrt{6^2-4^2}$

$c=\sqrt{20}$

$c=2\sqrt{5}$ , we know h=-2 and k=-3

Foci are $(-2,-3+2\sqrt{5})$ and $(-2,-3-2\sqrt{5})$

Option A is correct

6 0

3 years ago