Equation:
y=6,000(1.05)^5
Answer:
7657
Answer:
the first number is 5 the second number is 4
Step-by-step explanation:
first number = x
second number = y
X+2y=13 given this isolate x x = 13-2y
2x+y=14 substitute 13-2y for x
2(13-2y)+y=14
26-4y+y=14
-3y=-12
y=4 taking this number substitute into either equation above
x+2(4)=13
x+8=13
x=5
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Answer:
less
Step-by-step explanation:
Step-by-step explanation:
you don't show us the choices.
anyway, the real graph must be similar to the one you are showing, as it goes to - and + infinity for x = 2.
because the denominator "x-2" will be 0 for x = 2.
but the horizontal limits are both y = +3 (and not 0).
because (3x-2)/(x-2) goes more and more to 3/1 the larger (or smaller in the - direction) x gets.
