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ExtremeBDS [4]
2 years ago
11

PLEASE HURRY, ILL GIVE BRAINLIEST

Mathematics
2 answers:
Julli [10]2 years ago
8 0

Answer:

I= f.t = (50) (0.01) = (0.5) kg.m15

Step-by-step explanation:

vekshin12 years ago
8 0

jesus loves you and cares for you

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SUBTRACT: (6x3 - 7x2) - (- 7x4 + 7x3 + 8x2)
RSB [31]

Answer:

-5

Step-by-step explanation:

“x” would be multiplication, right?

5 0
2 years ago
Which exponential equation is equivalent to the logarithmic equation below? c = ln 2
Sophie [7]
\text{A logarithmic lemma: } \\ \text{It follows that: } \log_a a = 1
\text{Following this property, we can see that: } a^{\log_{a} a} = a
\text{Furthermore, we can create more general properties: } a^{\log_a b} = b

c = \log_e 2 \Rightarrow e^{c} = e^{\log_e 2} \\ \text{Using our third property, we see that: } e^{c} = 2
\text{And finally, this works for any } \log_{a} b \left\{a > 0, b \in \mathbb{R}\right\}
6 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 43 o
xeze [42]

Answer:

a) 95% of the widget weights lie between 29 and 57 ounces.

b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%

c) What percentage of the widget weights lie above 30? about 97.5%

Step-by-step explanation:

The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.  

a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.  

b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%

c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%

3 0
2 years ago
Need help finding the domain and range
pogonyaev

Here are a few things you'll need to know for this question:

  • Domain: <u>The list of x-values that are possible on a line.</u>
  • Range: <u>The list of y-values that are possible on a line.</u>
  • Interval Notation: <u>Shows the domain/range using the endpoints</u>. Brackets mean that the endpoint is included, parentheses mean the endpoint is excluded. Ex: (2,10]. 2 is excluded, 10 is included.
  • Closed Circles: <u>The endpoint is included.</u>
  • Open Circles: <u>The endpoint is excluded.</u>

So firstly, let's look at the domain. We see that there is a closed circle at x = -2 and an open circle at x = 5. Using what we know, <u>the interval notation of the domain is [-2,5).</u>

Next, let's look at the range. We see that there is a closed circle at y = -5 and an open circle at y = 2. Using what we know, <u>the interval notation of the range is [-5,2).</u>

3 0
3 years ago
Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo
Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

P(-4, 4) = (x_1, y_1)

E(0, -4) = (x_2, y_2)

m = 1, n = 3

Plug in the necessary values to find x and y coordinates for point Q as follows:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{1(0) + 3(-4)}{1 + 3}

x = \frac{0 - 12}{4}

x = \frac{-12}{4}

x = -3

y = \frac{my_2 + ny_1}{m + n}

y = \frac{1(-4) + 3(4)}{1 + 3}

y = \frac{-4 + 12}{4}

y = \frac{8}{4}

y = 2

The coordinates of the point Q are (-3, 2))

8 0
3 years ago
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