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3 years ago

Need help asap please!! This is the only one i don’t know i’m stuck!

Mathematics

1 answer:

lyudmila [28]3 years ago

6 0

Answer:

Reminder that is this form a(b)^x where a > 0

When b > 0 but < 1 that is a decay function

When b > 1 than its a growth function

Step-by-step explanation:

So following this you can figure out the answer

g(x)=0.3(x)

this is neither since there is no exponent (linear)

H=72(56)^t

this is growth since b = 56

A=(43)^t

this is growth since b = 43 ("a" is understood as "1")

H=5.9(0.82)^t

this is decay since b = 0.82

y=0.8(3.6)^t

this is growth since b = 3.6

f(t)=0.72(15)^t

this is growth since b = 14

A=49(8)^t

this is growth since b = 8

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Last year, 30% of the people who applied at a college were accepted. If 690 people were accepted, how many people applied?

Licemer1 [7]

Answer:

207 people applied

Step-by-step explanation:

690*30/100=207

690peole multiplied by 30 divide by 100=207 . I hope it's perfect .

4 0

3 years ago

What is the answer for the equation 3(5k+2) + 5= 3k-1

mina [271]

Answer:

12k + 12.

Step-by-step explanation:

=> 3(5k + 2) + 5 = 3k - 1

=> 15k + 6 + 5 = 3k - 1

=> 15k + 11 - 3k + 1

=> 12k + 12

Hence, correct answer is 12k + 12.

7 0

4 years ago

Read 2 more answers

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 more Small boxes sold than Large boxes.

Step-by-step explanation:

This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable.

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have two equations of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

Given Information:

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were 10 Large Boxes and 20 Small Boxes sold, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0

4 years ago

9/10

SIZIF [17.4K]

Answer: 90%

Step-by-step explanation: To write a fraction as a percent, first remember that a percent is a ratio of a number to 100.

So to write 9/10 as a percent, we need to find a fraction

equivalent to 9/10 that has a 100 in the denominator.

We can do this by setting up a proportion.

So we have $\frac{9}{10} = \frac{n}{100}$ .

Now, we can use cross-products to find the missing value.

So we have (9)(100) which is 900 is equal to (10)(n) or 10n.

So we have 900 = 10n.

Next, dividing both sides of the equation by 10, we have 90 = n.

So, 9/10 is equal to 90/100 or 90%.

7 0

4 years ago

Find the measure of side a. A = _ m

Oksi-84 [34.3K]

Sin(36)=a/16
16sin(36)=a
9.41=a

5 0

2 years ago