For this case we have to:
Given the quadratic equation of the form:

The roots are given by:

If we have: 
We can rewrite it in the following way:

Where:

Where we have:



By definition: 




Thus, the roots are given by imaginary numbers:

Answer:

Hello from MrBillDoesMath!
Answer: b
Discussion:
7b + 3 - 4b = 3 - 3(b+4) =>
7b + 3 - 4b = 3 - 3b -12 =>
(7b - 4b) + 3 = -3b - 9 =>
3b + 3 = -3b -9 => Add 9 to both sides
3b + 12 = -3b -9 + 9 =>
3b + 12 = -3b => ( add 3b to both sides)
6b + 12 = 0 => (subtract 12 from both sides)
6b = -12 =>
b = -12/6 = -2
Thank you,
MrB
I know this doesn't help but i'm on the same thing and i just don't know
It is (0,-1) hope that helps