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UkoKoshka [18]
2 years ago
7

Two workers can make two chairs in two days. How many chairs can 8 workers working at the same rate make in 20 days?

Mathematics
2 answers:
Norma-Jean [14]2 years ago
5 0
Every worker can make one chair each day. So 8 workers will make 8 chairs every day. So that's 8x20=160.
MakcuM [25]2 years ago
3 0
The answer is 4 chairs in 20 days
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The length of a rectangle is 6 feet more than three times the width of the
Nesterboy [21]

Answer:

<h2>width = 6 feet</h2>

Step-by-step explanation:

let l be the length of the rectangle

let w be the width of the rectangle

The statement

The length of a rectangle is 6 feet more than three times the width of the

rectangle is written as

l = 6 + 3w

From the question

l = 24 feet

Substitute the value into the above formula and solve for the width

That's

24 = 6 + 3w

3w = 24 - 6

3w = 18

Divide both sides by 3

w = 6

Therefore

<h3>width = 6 feet</h3>

Hope this helps you

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A machine shop produces heavy duty high endurance 20-inch rods that are meant for use in a variety of military grade equipment.
QveST [7]

Answer:

The probability that a defective rod can be salvaged = 0.50

Step-by-step explanation:

Given that:

A machine shop produces heavy duty high endurance 20-inch rods

On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.

If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.

Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20  - 15 )inches

Now:

P(X ≤ 5) = \dfrac{5}{20}

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P(X ≥ 15) = \dfrac{5}{20}

= 0.25

The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)

= 0.25+0.25

 = 0.50

∴ The probability that a defective rod can be salvaged = 0.50

4 0
2 years ago
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