Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
Test each
if angle is increased, rock will go further
if the angle starts at 0, then increases to 90 degrees (straight up) the rock will go up then bounce off of the launcher going either front or back, but vastly shorter than if it were pointed straight ahead
2nd one
changing angle change the distance
we see that is true
We can except 30/600 = 0.05>> 5%percent,
so 1000 * 0.05 = 50 parts defective
3 is 300,000 in 345,268.19
Hi again!
2x + y > 8
The correct answer is option D
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Honestly I don't think we can solve the equation to find the answer. What we can do is to find the boundary line. (I think you know what that is) After that, shading the appropriate area.
y > -2x + 8
Again, credit to my beautiful graphing calculator. Here is how it looks like.