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3 years ago

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The height, h, of a cylinder is 5 units less than 3 times its radius, r. Which expression represents the hight of the cylinder i

n terms of its radius

2 answers:

jeyben [28]3 years ago

7 0

You can do radius times 3 -5

emmasim [6.3K]3 years ago

6 0

Answer:

D) 3r-5h

Step-by-step explanation:

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100 POINTS<br> PLEASE PROVIDE STEPS<br> FIND FIRST DERIVATIVE AND SIMPLIFY ANSWER

BaLLatris [955]

Answer:

h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))

Step-by-step explanation:

h(x) = ln x / √(x² + 1)

You can either use quotient rule, or you can rewrite using negative exponents and use product rule.

h(x) = (ln x) (x² + 1)^(-½)

h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)

h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)

h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))

h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)

h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))

5 0

3 years ago

Read 2 more answers

Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He ass

pychu [463]

$N(s)= \frac{89s}{14+14( \frac{s}{17})^2 }
\\
\\N'(s)= (\frac{89s}{14+14( \frac{s}{17})^2 } )'= \frac{89\times 14(1+( \frac{s}{17})^2)-89s\times \frac{28}{17} }{14^2(1+( \frac{s}{17})^2)} 
\\
\\N'(s)=0
\\
\\89\times 14(1+( \frac{s}{17})^2)-89s\times \frac{28}{17}=0
\\
\\1+( \frac{s}{17})^2- \frac{2s}{17} =0
\\
\\289+s^2-34s=0
\\
\\s^2-34s+289=0
\\
\\(s-17)^2=0
\\
\\s=17
$

5 0

2 years ago

PLZ DO BOTH PARTS FOR 100 POINTS AND ILL DO ANYTHING!!!!

Kitty [74]

Step-by-step explanation:

<h3>Part A</h3>

<u>Multiply the energy produced in 1 second by the number of seconds:</u>

$3.9*10^{33} * 1.55*10^7 = 6.045*10^{40}$ erg

<h3>Part B</h3>

10⁻³ is same as 0.001 times and 10³ is same as 1000 times.

1.6*1000 = 1600 mm = 160 cm = 1.6 m is way too big for the measurement of the distance between the tracks on a CD.

So the first option is correct.

8 0

2 years ago

Read 2 more answers

Can we conclude that two similar figures can also be congruent figures? Explain.

shusha [124]

Answer:

In similar figures, the angles are congruent, even if the sides are not. Notice that one angle in each pair of figures corresponds to an angle in the other figure. They have the same shape but not the same size

7 0

3 years ago

an ellipse has a center at the origin , a vertex along the major axis at (13,0), and a focus at (12,0). What is the equation of

-BARSIC- [3]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Center = (0, 0)

Vertex = (13, 0)

Focus = (12, 0)

Process

From the data we know that it is a horizontal ellipse.

1.- Calculate "a", the distance from the center to the vertex.

a = 13

2.- Calculate "c", the distance from the center to the focus

c = 12

3.- Calculate b

Use the Pythagorean theorem to find it

a² = b² + c²

-Solve for b

b² = a² - c²

-Substitution

b² = 13² - 12²

-Simplification

b² = 169 - 144

b² = 25

b = 5

4.- Find the equation of the ellipse

$\frac{x^{2} }{13^{2}} + \frac{y^{2}}{5^{2}} = 1$ or $\frac{x^{2} }{169} + \frac{y^{2}}{25} = 1$

7 0

3 years ago