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MA_775_DIABLO [31]
3 years ago
9

What is 8/11 - 7/11 in simplest form

Mathematics
2 answers:
NARA [144]3 years ago
8 0

Answer:

It is 1/11

Step-by-step explanation:

Apply the rule a/c +- b/c = a+-b/c

=8-7/11

=1/11

Alexus [3.1K]3 years ago
8 0
Your answer is 1/11 because 8/11 - 7/11 in simplicity is in fact 1/11 because of math short form brainology
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2/3x+15=17 please and thank you
frozen [14]

Answer:

x=3

Step-by-step explanation:

2/3x+15=17

first subtract 15 from both sides

2/3x=2

multiply by 3 to eliminate the fraction

2x=6

divide by 3

x=3

7 0
3 years ago
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Need helps asap, im tryna get all of my work done today. So someone answer this fastt
xeze [42]

(4,-5) is Point C

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Estimate 62% of 196.<br> A. 80<br> B. 100<br> C. 120<br> O D. 140<br> HURRY PLEASE
Mrac [35]

Answer:

The answer is C: 120

Step-by-step explanation:

Ok so to solve this, you need to know that when "of" is in an equation, it always means multiply.

So 62% of 196 = 62% * 196.

62%  * 196 = 121.52

Then you need to round 121.52 to the nearest option, which is Option C: 120.

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2 years ago
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John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
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lesya [120]

I don't know the official answer but I can confirm for you that it is either C or D. I just don't remember how to determine which way the sign goes. Sorry

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