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3 years ago

What is the mean absolute deviation of the data set?

Mathematics

1 answer:

lana [24]3 years ago

6 0

15 + 16 + 15 + 8 + 6 = 60 divided by 5 = 12
Answer is D

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Five less than nine times a number is the same as nineteen more than the number

Xelga [282]

Answer:

Step-by-step explanation:

The first thing you need to do is develop the equation. Less in this case means subtract.

On the left side you have

9 times a number which is 9*x

5 less than 9 times a number means 9x - 5

Now you shift to the right

x = 3

x + 19 What you get is

9x - 5 = x + 19 Subtract x from both sides of the equation

9x - x - 5 = 19 Combine both x terms on the left

8x - 5 = 19 Add 5 to both sides.

8x - 5 + 5 = 19 + 5 Combine terms

8x = 24 Divide by 8

x = 24/8

x = 3

4 0

3 years ago

Encuentra la velocidad promedio de un móvil que durante su recorrido hacia el Norte tuvo las siguientes velocidades.

yan [13]

The mean or average speed of a mobile moving north is: Vprom= 20.575 m/sec

The average speed of a series of given speed values is calculated by summing each of the speeds and then dividing by the number of speeds , as follows:

Speeds:

V1=18.5m/s

V2=22m/s

V3=20.3m/s

V4=21.5m/s

V avg =?

Average V = ( V1+V2+V3 +V4)/4

Vavg = (18.5m/s + 22m/s +20.3m/s + 21.5m/s)/4

Vavg = 20.575nm/sec

To consult visit: brainly.com/question/11100327

5 0

2 years ago

Molly and Tess like to shop at the mall. Molly has $280 in her bank account and spends $40 every trip

Kobotan [32]

8 times. $280 divided by 40

8 0

3 years ago

what is the difference between the highest elevation in Alabama and the lowest elevation in Louisiana

tester [92]

Answer:

the difference is 2,415 feet.

Step-by-step explanation:

5 0

2 years ago

I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5

Gnesinka [82]

Given:
$f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}$

Using
$\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}$
we derive
$\frac{d}{dx}4xcos^{-1}(2x+4)$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}$

Similarly, using
$\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}$
we derive
$\frac{d}{dx}(-\sqrt{3-3x^2})$
$=\frac{3x}{\sqrt{3-3x^2}}$

Therefore, the derivative is
$f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}$

3 0

3 years ago

Read 2 more answers