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steposvetlana [31]
3 years ago
9

Write each height using scientific notation 1700000000 and 152000000

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0
1.7 times 10 to the 9 power 1.52 times10 to the 8 power
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Find tan 0.<br> (Marking brainliest if correct) <br><br> 8/17<br> 15/17<br> 15/8<br> 8/15
Rina8888 [55]

Answer:

15/8

Step-by-step explanation:

Assuming you mean tan theta

Tan(theta) = opposite/adjacent

We know the adjacent side is 8 so the bottom of the fraction must also be 8

C: 15/8 is the only option that fits this criteria

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2 years ago
A square is shown below. Which expression can be used to find the area, in square units, of the
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8 units OA 4.4 2 1 OB 44 oc 8.8 20.4-8-8
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Can you simplify 6/60?
Slav-nsk [51]
Yes divide by 6 both top and bottom and u get 1/10
8 0
3 years ago
Read 2 more answers
A triangle has a side length of 15 inches and 30 inches.It also has angels that measures 45 and 20.Which of the following identi
Alika [10]
I am assuming that you will need to do Pythagorus Theorem to find the 3rd side length. If thats the case then you will need to do the following formula : a^2 + b^2 = <span>√(c) 
So 15^2 + 30^2 = </span>√(c)
= 33.5 inches

The third angle would be 115 because 180 - 45 - 20 = 115

I hope this helped.
7 0
3 years ago
The perimeter of a triangle is 41 inches. The three sides of the triangle are all differnt lenghts. The longest side is 10 less
erma4kov [3.2K]

Answer:

Longest\ side=20\ inches\\\\Middle\ side=15\ inches\\\\Shortest\ side=6\ inches

Step-by-step explanation:

Let be "x" the lenght of the longest side, "y" the lenght of the middle side and "z" the lenght of the shortest side.

The perimeter is:

41=x+y+z       [Equation 1]

We know that the longest side is 10 less than twice the middle side length. This can be expressed as:

x=2y-10          [Equation 2]

And the middle side length is three less than three times the shortest side length. This is:

y=3z-3         [Equation 3]

The steps are:

- Solve for "z" from the third equation:

y=3z-3\\\\y+3=3z

z=\frac{y+3}{3}    [Equation 4]

- Substitute [Equation 4] into [Equation 1]

- Substitute [Equation 2] into [Equation 1]

Then:

41=(2y-10)+y+(\frac{y+3}{3})

- Solve for "y":

41=2y-10+y+\frac{y+3}{3}\\\\41=2y-10+y+\frac{y}{3}+1\\\\41=\frac{10}{3}y-9\\\\41+9=\frac{10}{3}y\\\\\frac{50*3}{10}=y\\\\y=\frac{150}{10}\\\\y=15

- Substitute this value into [Equation 2] and into [Equation 4]:

x=2(15)-10\\\\x=20

z=\frac{(15)+3}{3}\\\\z=6

4 0
3 years ago
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