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3 years ago

7

A student's cost for last semester at her community college was $2000. She spent $360 of that on books. What percent of last

semester's college costs was spent on books?

1 answer:

Lostsunrise [7]3 years ago

5 0

Answer:

18%

Step-by-step explanation:

360/2000=0.18

0.18x100=18

So the answer is 18%.

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Select one:<br> a. 4<br> b.5<br> c. 6<br> d. 7

tino4ka555 [31]

Answer:

C

Step-by-step explanation:

Given 2 secants intersect a circle from a point outside the circle, then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 10 + x) = 6(6 + 10 + x)

x(2x + 10) = 6(16 + x) ← distribute parenthesis on both sides

2x² + 10x = 96 + 6x ← subtract 96 + 6x from both sides

2x² + 4x - 96 = 0 ← in standard form

Divide through by 2

x² + 2x - 48 = 0 ← factor the left side

(x + 8)(x - 6) = 0

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 6 = 0 ⇒ x = 6

However x > 0 ⇒ x = 6 → C

7 0

3 years ago

Mrs. Welch and her 7 children are shopping at a local grocery store. Each of the children will be allowed to select one box of c

Sholpan [36]

Answer: I am pretty sure the answer is 40,320

Step-by-step explanation:

If you do 8x7x6x5x4x3x2 it equals 40,320

7 0

3 years ago

What is the percentage between 1192.64 and 819.73

Licemer1 [7]

1192.64-819.73 is 372.91

so... if we take 1192.64 to be the 100%, how much is 372.91 in percentage then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1192.64&100\\
372.91&p
\end{array}\implies \cfrac{1192.64}{372.91}=\cfrac{100}{p}\implies p=\cfrac{372.91\cdot 100}{1192.64}$

3 0

3 years ago

Is this a function ?

erica [24]

Answer:

I do not believe this is a function because the points on the graph are above each other on one line.

Step-by-step explanation:

6 0

3 years ago

Simplify the complex fraction.

lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}$

Step 2: Simplify the denominator

$$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}$

Step 3: Using step 1 and step 2

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}$

Step 4: Using fraction rule:

$$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}$

$$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}$

Cancel the common factor r and t², we get

$$=\frac{64 r^{2} \cdot 9 }{16 \cdot 15 t^2 }$

Cancel the common factors 16 and 3 on both numerator and denominator.

$$=\frac{4 r^{2} \cdot 3 }{ 5 t^2 }$

$$=\frac{12 r^{2} }{ 5 t^2 }$

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2} }{ 5 t^2 }$

The simplified fraction is $\frac{12 r^{2} }{ 5 t^2 }$ .

5 0

3 years ago