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NemiM [27]
3 years ago
6

Why do computers use zeros and ones? a. because combinations of zeros and ones can represent any numbers and characters b. becau

se digital devices have two stable states and it is natural to use one state for 0 and the other for 1 c. because binary numbers are simplest d. because binary numbers are the bases upon which all other number systems are built
Computers and Technology
1 answer:
Leni [432]3 years ago
8 0

Answer:

B. because digital devices have two stable states and it is natural to use one state for 0 and the other for 1

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You should check your battery ___________. Every week Never Every six months Every 30,00 miles
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3 years ago
Write two recursive versions of the function minInArray. The function will be given a sequence of elements and should return the
Viktor [21]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;//using namespace

int minInArray1(int arr[],int arrSize)//declaring method minInArray1

{

if(arrSize == 1)//use if block to check arrSize value is equal to 1  

{

return arr[0];//return first element of array

}

else //defining else block

{

int max= minInArray1(arr, arrSize-1);//use integer variable max to call method recursively  

if(arr[arrSize-1] < max)//use if block to check array value  

{

max = arr[arrSize-1];//use max to hold array value

}

return max;//return max variable value

}

}

int minInArray2(int arr[], int low, int high)//defining a method minInArray2  

{

if(low == high) //use if to check low and high variable value are equal

{

return arr[low];//return low variable value

}

else //defining else block

{

int minimum = minInArray2(arr, low+1, high);//defining integer variable minimum to call method minInArray2 recursively

if(arr[low] < minimum)

{

minimum = arr[low];//use minimum variable to hold array value

}

return minimum;//return minimum value

}

}

int main()//defining main method

{

int arr[10] = { 9, -2, 14, 12, 3, 6, 2, 1, -9, 15 };//defining an array arr

int r1, r2, r3, r4;//defining integer variable

r1 = minInArray1(arr, 10);//use r1 variable to call minInArray1 and hold its return value

r2 = minInArray2(arr, 0, 9);//use r1 variable to call minInArray2 and hold its return value

cout << r1 << " " << r2 << endl; //use print method to print r1 and r2 variable value

r3 = minInArray2(arr, 2, 5);//use r3 variable to call minInArray1 and hold its return value

r4 = minInArray1(arr + 2, 4); //use r4 variable to call minInArray2 and hold its return value

cout<<r3<< " " <<r4<<endl; //use print method to print r3 and r4 variable value

return 0;

}

Output:

please find the attached file.

Explanation:

In the given code two methods, "minInArray1 and minInArray2" is defined,  in the "minInArray1" it accepts two-variable "array and arrSize" as the parameter, and in the "minInArray2" method it accepts three integer variable "array, low, and high" as the parameter.

  • In the "minInArray1" method, and if the block it checks array size value equal to 1 if the condition is true it will return the first element of the array, and in the else block the max variable is defined, that calling method recursively
  • and store its value.
  • In the "minInArray2" method, an if the block it checks low and high variable value is equal. if the condition is true it will return a low array value. In the next step, the minimum value is defined, which checks the element of the array and uses a low array to store its value.
  • In the main method an array and four integer variable "r1, r2, r3, and r4" is defined, which calls two methods "minInArray1 and minInArray2" and use print method to print its value.
7 0
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A small monster collector has captured ten Bagel-type small monsters. Each Bagel-type small monster has a 35% chance of being a
Doss [256]

Answer:

Check the explanation

Explanation:

Each Bagel-type small monster has 0.35 probability of being a Sesame Seed-subtype and 0.2 probability of being a Whole Wheat-subtype.

The probability that exactly 8 of them are Whole Wheat-subtype is \binom{10}{8}(0.2)^8(0.8)^2 using multiplication principle, because first need to choose which 8 are Whole Wheat-subtype, and if exactly 8 of them are Whole Wheat-subtype, then other two are not Whole Wheat-subtype. The former has probability 0.2, while the latter has probability 1-0.2 = 0.8 .

Kindly check the attached images below for the complete answer to the question above

6 0
3 years ago
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