Hi why we use sin in vector product why not we use cosine?
1 answer:
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We can start by finding the gradient of LM
Two perpendicular lines will meet the requirement
×
=-1
Two parallel lines have equal gradients
NM is perpendicular to LM, hence the gradient of NM is -1
KN is a line that is parallel to NM, hence the gradient is 1
KL is perpendicular to LM, hence the gradient of KL is -1
Two perpendicular lines will meet the requirement
Two parallel lines have equal gradients
NM is perpendicular to LM, hence the gradient of NM is -1
KN is a line that is parallel to NM, hence the gradient is 1
KL is perpendicular to LM, hence the gradient of KL is -1