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xz_007 [3.2K]
3 years ago
12

you only have to answer one, dont answer one thats been answered. also english please im a baby who wont learn new languages.

Mathematics
2 answers:
shepuryov [24]3 years ago
4 0

Answer:

1. x=11

Step-by-step explanation:

2x+5=27

Subtract 5 from both sides

2x=22

Divide 2 from both sides

x=11

Keith_Richards [23]3 years ago
4 0

Answer:

1. 11

2. -3

3. 7

Step-by-step explanation:

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Answer:

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<em><u>Or ;</u></em>

{( \sqrt{ {x}^{ - 3} } )}^{5}  =  {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5}  = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5}  \\  \\  =  ( { \frac{1}{ \sqrt{x}  \sqrt{ {x}^{2} } } })^{5}  =  ({ \frac{1}{ x\sqrt{x} }})^{5}   \\  \\  = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{1}{2} \times 5 } }  \\  \\  =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{5}{2} } }  =  \frac{1}{ {x}^{5}  \sqrt{ {x}^{5} } }  \\  \\  =  \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1}  }  }  =  \frac{1}{ {x}^{5}  \sqrt{x}  \sqrt{( { {x}^{2} })^{2} } }  \\  \\  =  \frac{1}{ {x}^{5} {x}^{2}  \sqrt{x}  }  =  \frac{1}{ {x}^{7} \sqrt{x}  }   =  \frac{ \sqrt{x} }{ {x}^{8} }

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1 year ago
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What would be the answer to this problem <img src="https://tex.z-dn.net/?f=%5Cfrac%7B7x-3%7D%7B9%7D%20%5Cgeq%208-2x" id="TexForm
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