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xz_007 [3.2K]
3 years ago
12

you only have to answer one, dont answer one thats been answered. also english please im a baby who wont learn new languages.

Mathematics
2 answers:
shepuryov [24]3 years ago
4 0

Answer:

1. x=11

Step-by-step explanation:

2x+5=27

Subtract 5 from both sides

2x=22

Divide 2 from both sides

x=11

Keith_Richards [23]3 years ago
4 0

Answer:

1. 11

2. -3

3. 7

Step-by-step explanation:

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What is the scale of a bar graph
kirill115 [55]
The scale of a bar graph is the range of values presented along the horazontil and vertical axis

7 0
4 years ago
A cylinder has a base diameter of 8 inches and a height of 7 inches. What is its volume in cubic inches, to the nearest tenths p
DaniilM [7]

Answer:

351.9 cubic in

Step-by-step explanation:

The volume of a cylinder is hr²π.

r is half the diameter, so 8/2 is 4.

Plug in your h and r and get:

7 * 4² * π

7 * 16 * π

112π

Multiply the π and you'll get about 351.9 cubic in

7 0
3 years ago
The sum of the masses of two heavyweight boxers is 190kg. ⅘ the heavier boxer is 10kg less than the mass of lighter boxer. Find
ratelena [41]

Answer:

<em>Their masses are 100 kg and 90 kg</em>

Step-by-step explanation:

<u>Equations</u>

We'll solve the problem by setting only one variable. Let's call:

x = weight of the heavier boxer

Since the sum of the masses of both boxers is 190 Kg:

190 - x = mass of the lighter boxer.

It's given that \frac{4}{5} of the mass of the heavier boxer is 10 kg less than the mass of the other, thus:

\displaystyle \frac{4}{5}x=190-x-10

Operating:

\displaystyle \frac{4}{5}x=180-x

Multiplying by 5:

\displaystyle 4x=5(180-x)

\displaystyle 4x=5*180-5x

Simplifying:

\displaystyle 9x=900

x=\frac{900}{9}=100

The heavier boxer's mass is 100 kg. The lighter boxer has a mass of 190-100 = 90 kg.

Their masses are 100 kg and 90 kg

5 0
3 years ago
In △ABC, point P∈ AC with AP:PC=1:3, point Q∈AB so that AQ:QB=3:4, Find the ratios APBQ : APBC and AAQP : AABC.
weqwewe [10]

Answer: The  ratios APBQ : APBC=4:21 and AAQP : AABC= 3:28

Explanation:

Here, ABC is a triangle where, P and Q are the midpoints of the edges AC and AB respectively,

Now, according to the question ,AP:PC=1:3 let AP=x and PC=3x where x is any real number. Thus, AC=AP+AC= x+3x= 4x

Similarly,  AQ:QB=3:4 let AQ=3y and QB=4y where y is also any real number. Thus, AB=AQ+QB=3y+4y=7y

Since, \frac{AP.BQ}{AP.BC} =\frac{AP.BQ}{AB.PC} =\frac{x.4y}{7y.3x} =\frac{4xy}{21xy} =\frac{4}{21}

And, \frac{AA.QP}{AA.BC} =\frac{AQ.AP}{AB.AC} =\frac{3y.1x}{7y.4x} =\frac{3xy}{28xy} =\frac{3}{28}

5 0
4 years ago
Simplify to create an equivalent expression <br> -4(-11 + 4n) -3(-2n + 9)
Marizza181 [45]

Answer:

-71 + 22n is the equivalent expression.

This is the simplified expression.

Step-by-step explanation:

4(-11 + 4n) -3(-2n + 9)

= -44 + 16n + 6n - 27

= -44 + 22n - 27

= -71 + 22n

7 0
3 years ago
Read 2 more answers
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