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velikii [3]
4 years ago
6

(PICTURE IS FOR #1 aka QUESTION 3)

Mathematics
1 answer:
kifflom [539]4 years ago
6 0
Question 3: there are 5 colors, the chance that you get yellow is 1/5 or 20%

Question 4:
I don't know a normal die so i can't help you

Question 5:
The best way is B, decimal
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While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en
AVprozaik [17]

Answer:

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057  

p_v =P(Z>0.0057)=0.4977  

The p value is a very high value and using the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.  

Step-by-step explanation:

1) Data given and notation  

X_{M}=23 represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

X_{W}=8 represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

n_{M}=66 sample of male selected

n_{W}=23 sample of demale selected

p_{M}=\frac{23}{66}=0.34848 represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

p_{W}=\frac{8}{23}=0.34782 represent the proportion of women with red/green color blindness  

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:  

Null hypothesis:p_{M} \leq p_{W}  

Alternative hypothesis:p_{M} > p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057  

4) Statistical decision

Using the significance level provided \alpha=0.05, the next step would be calculate the p value for this test.  

Since is a one side right tail test the p value would be:  

p_v =P(Z>0.0057)=0.4977  

So the p value is a very high value and using the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.  

4 0
4 years ago
in your class , 0.58 of the students bring a piece of whole fruit for a snack and 0.36 of the students bring a snack pack of cra
JulsSmile [24]

So an easier way to look at this is to think of the decimals as percentages, to convert these decimals to percentages we can multiply each by 100.

Which gives us 58% of students with fruit, and 36% students with crackers. We know that 58% is much larger than 36%, so more students bring fruit instead of crackers.

6 0
3 years ago
2x(8+7)-6/2x(9-3) evaluate
Katarina [22]
Ok so assuming that the 'x' means multiply and not 'x' as in placeolder we do

PEMDAS
parenthaseees
exponents
multipilcation or division
additon or subtraction

parethasees simplify first
(8+7)=15


(9-3)=6

now we have
2x(15)-6/2x(6)
multiply
2x15=30

6/2x6=36/2=18

now we have
30-18
12

answer is 12
6 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
stiv31 [10]

8,9,10

That is the answer

4 0
3 years ago
Read 2 more answers
To calculate a batting average, divide the player's number of hits by the total number of at-
IrinaK [193]

Answer:

.25

Step-by-step explanation:

50÷195=.2564102564

about a 25% chance to hit the ball

4 0
3 years ago
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