Formula for this case is
(a+b)∧3=a∧3+3a∧2b+3ab∧2+b∧3
(2x+5)∧3=(2x)∧3+3*(2x)∧2*5+3*2x*5∧2+5∧3=8 x∧3+3*4x∧2*5+3*2x*25+125=
=8x∧3+60x∧2+150x+125
Good luck!!!
Answer:
Y(n) = 7n + 23
Step-by-step explanation:
Given:
f(0) = 30
f(n+1) = f(n) + 7
For n=0 : f(1) = f(0) + 7
For n=1 : f(2) = f(1) + 7
For n=2 : f(3) = f(2) + 7 and so on.
Hence the sequence is an arithmetic progression with common difference 7 and first term 30.
We have to find a general equation representing the terms of the sequence.
General term of an arithmetic progression is:
T(n) = a + (n-1)d
Here a = 30 and d = 7
Y(n) = 30 + 7(n-1) = 7n + 23
Answer:
There's not enough information to determine the answer... is there more to this?
Answer:
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A because if you use T3 it wouldn’t have make sense so only reasonable and solution that works is A