Divide 204 to 10.2 or add and then u can get your final answer, you can also multiple.
Let's assume
the number of hours Susan jogs at the increased speed is 't' hours
Since, increased speed is 6 miles per hour
after 't' hours , she travles with increased speed is 6*t miles
She starts off with a half-hour walk at a pace of 2 miles per hour
so, she travels distance
=0.5*2 miles
=1 miles
She travels a total of 4 miles
total distance is
=6t+1
now, we can set them equal

now, we can solve for t
Subtract both sides by 1


Divide both sides by 6
we get

so, the number of hours Susan jogs at the increased speed is 0.5 hrs.........Answer
Answer:
b=-0.0019a + 215
at 2500 ft, b=210.25 degrees F
Step-by-step explanation:
First find the slope. a=altitude, b = temperature
slope is b2-b1 / a2-a1
points are (8200, 199.42) and (4700, 206.07)
(206.07 - 199.42) / (4700-8200)
= 6.65/ -3500
= - 0.0019
we have b = -0.0019a + intercept
plug in a point to find intercept
199.42 = -0.0019*8200 + intercept
intercept = 199.42 + 15.58 = 215
b=-0.0019a + 215
at a=2500 ft, substitute into equation
b= -0.0019*2500 + 215
= -4.75 + 215
= 210.25 degrees F
please give thanks by clicking heart button :)