1) Call x the sample mean = 3.56
2) Call s the sample standard deviation = 0.2
3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:
x +/- Z(0.5) s/√n
Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.
Z(0.5) = 0.3085
Then the inteval is
x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
9:00 to 3:45 = 6 hours 45 min
1 lesson = 55 min
6 lessons = 5 hours 30 min
5.3 + 0.25 = 5 hours 55 min
6.45 - 5.55 = 50 min
lunch = 50 min
48 2 96
—- • —- = —- 96/3 = 32 48-32 = 16
1 3 3
So her hair is 16 inches long now
Answer:

Step-by-step explanation:

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we have:
=
the terms have the same base (x), then we write the same base and sum the exponents:
