I really don’t know but I think I got it wrong
Answer:
Step-by-step explanation:
y = 9 - X is a linear function; x is to the first power.
y = x2 + 1 does NOT represent a linear function; it's a quadratic function.
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y=x² + 5 does NOT represent a linear function; it's a quadratic function.
D)
y = [xl - 9 does NOT represent a linear function; it's an absolute value function. This function has two halves, each of which is a linear function.
But the best answer here is that y = 9 - X is a linear function; x is to the first power.
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
The answer could be (7+k)÷2
