All categories

3 years ago

If right answer I will give brainly and 90 points

Mathematics

1 answer:

aleksklad [387]3 years ago

6 0

Answer:

i can bet my brainliest that the answer is c

Step-by-step explanation:

You might be interested in

Which are perfect squares? Check all that apply. 49 17 g 143 225

Vika [28.1K]

<span>49 17 g 143 225
</span><span>
you have g in here
is g is 9?

perfect squares
49 = 7^2
225 = 15^2</span>

5 0

3 years ago

Read 2 more answers

Solve for the variable. if necessary, round to the nearest tenth.

Yanka [14]

Answer:

b. 8 is the correct answet it's clearly

7 0

2 years ago

What is the equation of a line that passes through (4, 7) and has a slope of −14?

deff fn [24]

Slope = -1/4
(4, 7)

y - 7 = -1/4 (x - 4)
y - 7 = -1/4x + 1
y = -1/4 + 8

answer is C

5 0

3 years ago

1) There are 80 grams of salt in a 32% solution. Find the weight of the solution

alukav5142 [94]

Answer:

Weight of the solution = 250 grams

Step-by-step explanation:

1) Consider the weight of solution as x grams.

32 % solution = 80 grams salt

32% of x = 80

(32/100)*x = 80

Solving for x:

x = (80*100) / 32

x = 250 grams

7 0

3 years ago

Simplify the complex fraction.

lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}$

Step 2: Simplify the denominator

$$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}$

Step 3: Using step 1 and step 2

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}$

Step 4: Using fraction rule:

$$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}$

$$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}$

Cancel the common factor r and t², we get

$$=\frac{64 r^{2} \cdot 9 }{16 \cdot 15 t^2 }$

Cancel the common factors 16 and 3 on both numerator and denominator.

$$=\frac{4 r^{2} \cdot 3 }{ 5 t^2 }$

$$=\frac{12 r^{2} }{ 5 t^2 }$

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2} }{ 5 t^2 }$

The simplified fraction is $\frac{12 r^{2} }{ 5 t^2 }$ .

5 0

3 years ago