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Rudik [331]
3 years ago
15

What are fractions?​

Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

a numerical quantity that is not a whole number

Darya [45]3 years ago
5 0

Answer:

Fractions are parts of a whole.

Step-by-step explanation:

Fractions include a numerator and a denominator.

EXAMPLE:

x/y it can also be x÷y. x would be the numerator, y would be the denominator.

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Taylor estimates that the faucet in her kitchen drips at a rate of 1 drop every 2 seconds. James wants to know how many times he
Vsevolod [243]

Answer:

302400

Step-by-step explanation:

3 0
3 years ago
What are these answers?
murzikaleks [220]
The first one is 25/9
And the second one is 25/36
8 0
2 years ago
Han drinks three gallons of iced tea each day. Each gallon of iced tea contains ¾ cups of sugar. How much sugar does Han drink w
erica [24]

Answer:

3 cups of sugar.

Step-by-step explanation:

Han drinks 3/4 of a cup of sugar each day when she drinks iced tea. She drinks 3 gallons, and each contains 3/4. If each contains only 3/4, we will have to multiply 3/4 by 3 gallons to find our answer to this question.

\frac{3}{4} = 1 \text{-gallon}

So, now we will have to multiply 3/4 by the number 3.

\frac{3}{4} × 3 = \frac{12}{4}

12/4 is equal to 3, so the answer is 3.

7 0
2 years ago
A+restaurant+bill+before+tax+is+$15. 50. +if+the+sales+tax+is+8%+and+a+15%+tip+is+added,+what+is+the+total+cost+of+the+meal?
ZanzabumX [31]

Answer:

$19.07

Step-by-step explanation:

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7 0
2 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
2 years ago
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