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kirza4 [7]
3 years ago
15

What ia the order of 1 2/3 , 1 1/6 and 1 5/6

Mathematics
1 answer:
Fittoniya [83]3 years ago
5 0
1 1/6, 1 2/3, 1 5/6 is the order. :) hope I helped!
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\bf \begin{cases}&#10;\quad3x+2y=-9\\&#10;-10x+5y=-5&#10;\end{cases}

so hmm the idea behind the elimination, is to make the value atop or below, of either variable, the same but with a negative sign

so hmmm say... we'll eliminate "y"

so... let's see, we have 2y and 5y, both positive
what do we multiply 2y to get a negative -5y, that way, -5y +5y = 0 and poof it goes

well let's see, let's try "k"     \bf 2yk=-5y\implies k=-\cfrac{5y}{2y}\implies k=-\cfrac{5}{2}

so.. if we multiply 2y by -5/2, we'll end up with -5y

well, let's multiply that first equation then by -5/2

\bf \begin{array}{rllll}&#10;3x+2y=-9&\qquad\times -\frac{5}{2}\implies &-\frac{15}{2}x-5y=\frac{45}{2}\\\\&#10;-10x+5y=-5&\implies &-10x+5y=-5\\&#10;&&---------\\&#10;&&\frac{-35}{2}x+0\quad=\frac{35}{2}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;\cfrac{-35}{2}x=\cfrac{-35}{2}\implies \cfrac{-35x}{2}=\cfrac{-35}{2}\implies x=\cfrac{2}{-35}\cdot \cfrac{-35}{2}&#10;\\\\\\&#10;\boxed{x=1}

so.. now we know x = 1.... so let's plug that in  say hmmm 2nd equation

\bf -10(1)+5y=-5\implies -10+5y=-5\implies 5y=5\implies\boxed{ y=1}
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