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ololo11 [35]
3 years ago
13

Find an equation of variation in which y varies inversely as x and y=5 and x=21. Then find the value of y when x=10.

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 5 , x = 21

k = yx = 5 × 21 = 105

y = \frac{105}{x} ← equation of variation

When x = 10, then

y = \frac{105}{10} = 10.5

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The graph of y=f(x) is shown below. Draw the graph of y=-f(x)
valkas [14]

Answer:

y = -f(x): reflection over x axis

Step-by-step explanation:

y = -f(x): reflection over x axis

8 0
2 years ago
I need help please in the number 2
ANEK [815]
2x3=6
3x2=6
6 divided by 2=3
6 divided by 3=2
7 0
3 years ago
Please explain how you got your answer!!! The dot plots below show the ages of students belonging to two groups of salsa classes
Rudik [331]

Answer:

Group b most likely has a lower mean age of salsa students

Step-by-step explanation:

Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.

Here we are given with two groups that are Group A and Group B

both having total number of students = 20

Here the mean age of the data is addition of the all ages of different students divided by total number of students.

For group a

total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29

= 15 + 40 + 102 + 96 + 87

=340

The mean age of salsa students= 340 ÷ 20 = 17

For group b

total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21

= 42 + 30 + 56 + 80 + 42

=250

The mean age of salsa students= 250 ÷ 20 = 12.5

So the group b most likely has a lower mean age of salsa students

Learn more about Arithmetic Mean here - brainly.com/question/24688366

#SPJ10

7 0
2 years ago
Y1=4(5x-1), y2-=5x+1 and y1 is 344 more than 2 times y2
alisha [4.7K]
 y_1=4(5^x-1) and y_2=5^x+1

y_1=344+2y_2
y_1=344+2(5^x+1)
4(5^x-1) = 344 + 2(5^x+1)
(4)(5^x)-4=344+2(5^x)+2
4(5^x)-2(5^x)=344+2+4
2(5^x)=350
5^x= \frac{350}{2}
5^x=175
log(5^x)=log(175)
x(log(5))=log(175)
x= \frac{log175}{log5}
x=3.21 (rounded to two decimal places)
4 0
3 years ago
Line perpendicular to the line that goes through (0,0) and (3,2)
KonstantinChe [14]
Since the first line passes thru the origin, you can read off its slope from the coordinates of the other point (3,2):  the slope is m = 2/3.

A line perpendicular to the first has slope -3/2, the negative reciprocal of 2/3.

Thus, the perpendicular line is    y = (-3/2)x + b.  Subbing 0 for y and 0 for x, we get b = 0.  Therefore, the equation of this new line is y = (-3/2)x.

7 0
3 years ago
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