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ololo11 [35]
3 years ago
13

Find an equation of variation in which y varies inversely as x and y=5 and x=21. Then find the value of y when x=10.

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 5 , x = 21

k = yx = 5 × 21 = 105

y = \frac{105}{x} ← equation of variation

When x = 10, then

y = \frac{105}{10} = 10.5

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Evaluate each function at each of the four points.
Mumz [18]

Answer:

Step-by-step explanation:

All we have to do is input the given values of x into the functions.

The first function:

f(x) = x^2 - 5x - 6

f(0) = 0^2 - 5(0) - 6 = 0 - 0 - 6 = -6

f(0) = -6

f(2) = 2^2 - 5(2) - 6 = 4 - 10 - 6 = -12

f(2) = -12

f(-1) = -1^2 - 5(-1) - 6 = 1 + 6 - 6 = 1

f(-1) = 1

f(6) = 6^2 -5(6) - 6 = 36 - 30 - 6 = 0

f(6) = 0

The second function:

f(x) = x^3 - x^2 - 12

f(0) = 0^3 - 0^2 - 12 = 0 - 0 - 12 = -12

f(0) = -12

f(2) = 2^3 - 2^2 - 12 = 8 - 4 - 12 = -8

f(2) = -8

f(-1) = -1^3 - (-1)^2 - 12 = -1 - 1 - 12 = -14

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f(6) = 6^3 - 6^2 - 12 = 216 - 36 - 12 = 168

f(6) = 168

The third function:

f(x) = 5 * 2^x

f(0) = 5 * 2^0 = 5 * 1 = 5

f(0) = 5

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f(2) = 20

f(-1) = 5 * 2^-1 = 5 * 0.5 = 2.5

f(-1) = 2.5

f(6) = 5 * 2^6 = 5 * 64 = 320

f(6) = 320

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Step-by-step explanation:

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Answer:

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The given numbers are 78 & 80

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step 3 Divide the sum by 2 to get the average.

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