PLEASE HELP ME WITH MY GEOMETRY HOMEWORK!!!!1

Find the factors of each expression. x^2+36

OleMash [197]

Answer:

<h2>x²+36+2(x)(6).. is the correct answer.. </h2>

4 0

2 years ago

Solve. 4x−y−2z=−8 −2x+4z=−4 x+2y=6 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=

ladessa [460]

Answer:

(-2, 4, -2)

x=-2, y=4, z=-2.

Step-by-step explanation:

So we have the three equations:

$4x-y-2z=-8\\-2x+4z=-4\\x+2y=6$

And we want to find the value of each variable.

To solve this system, first look at it and consider what you should try to do.

So we can see that the second and third equations both have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all xs.

Therefore, let's first isolate the variable in the second and third equation.

Second Equation:

$-2x+4z=-4$

First, divide everything by -2 to simplify things:

$x-2z=2$

Subtract x from both sides. The xs on the left cancel:

$(x-2z)-x=2-x\\-2z=2-x$

Now, divide everything by -2 to isolate the z:

$z=-\frac{2-x}{2}$

So we've isolated the z variable. Now, do the same to the y variable in the third equation:

$x+2y=6$

Subtract x from both sides:

$2y=6-x$

Divide both sides by 2:

$y=\frac{6-x}{2}$

Now that we've isolated the y and z variables, plug them back into the first equation. Therefore:

$4x-y-2z=-8\\4x-(\frac{6-x}{2})-2(-\frac{2-x}{2})=-8$

Distribute the third term. The -2s cancel out:

$4x-(\frac{6-x}{2})+(2-x)=-8$

Since there is still a fraction, multiply everything by 2 to remove it:

$2(4x-(\frac{6-x}{2})+(2-x))=2(-8)$

Distribute:

$8x-(6-x)+2(2-x)=-16\\8x-6+x+4-2x=-16$

Combine like terms:

$8x+x-2x-6+4=-16\\7x-2=-16$

Add 2 to both sides:

$7x=-14$

Divide both sides by 7:

$(7x)/7=(-14)/7\\x=-2$

Therefore, x is -2.

Now, plug this back into the second and third simplified equations to get the other values.

Second equation:

$z=-\frac{2-x}{2}\\ z=-\frac{2-(-2)}{2}\\z=-\frac{4}{2}\\z=-2$

Third equation:

$y=\frac{6-x}{2}\\y=\frac{6-(-2)}{2}\\y=\frac{8}{2}\\y=4$

Therefore, the solution is (-2, 4, -2)

3 0

3 years ago

Read 2 more answers

I put a random encouraging message on here just to spread some positivity/encouragement, and someone deleted it because it "went

malfutka [58]

Answer:

It was probably just because it wasnt a question.

Step-by-step explanation:

Hope this helps! Plz give brainliest!!

4 0

2 years ago

Como podríamos saber cuantos camellos le corresponden a cada hermano en realidad

SCORPION-xisa [38]

Answer:

Eldest brother = 18 camels

2nd brother = 12 camels

Youngest brother = 4 camels

Step-by-step explanation:

Question posted:

How could we know how many camels actually correspond to each brother?

It is from "the man who calculated":

The question is incomplete without the background information.

Based on the question, It has to do with sharing an inheritance of 35 camels among 3 brothers.

"The man who calculated", by Malba Tahan.

Since the complete question isn't available, we are going to look at the following question to understand how to do the calculation.

Question:

How can an inheritance of 35 camels be divided among three brothers in such a way that the eldest brother gets half of them, the second one gets 1/3 of the total and the youngest brother gets 1/9 of the total camels?

Solution:

Total number of camels= 35

Eldest brother gets half: 1/2 of 35 gives a fraction and not an whole number

2nd brother = 1/3 of 35 (gives a fraction)

3rd brother = 1/9 of 35 (gives a fraction)

Since we can't have a camel in fraction except in whole number, we would look for the closest number to 35 that would be divided by 2, 3 and 9 respectively without giving a fraction.

Number 36 is the closest number to 35 that satisfies this condition.

1st brother = 1/2 × 36 = 18 camels

2nd brother = 1/3 × 36 = 12 camels

3rd brother = 1/9 × 36 = 4 camels

Now let's add the camels the 3 brother got together = 18 + 12 + 4 = 34 camels

Total camels - amount shared = 35 -34 = 1

Meaning one camel is remaining. The distributor would keep the remaining one as that's the way such distributions could be achieved.

8 0

3 years ago

Consider triangle ABC where AB=X+5, BC=X-2, area is 30cm squared. Find X by solving X^2+3X-70=0, and find the perimeter.

klasskru [66]

Answer:

What the hell AC is not given so you can't find the Perimeter

Step-by-step explanation:

x^2+3x-70=0

(x-7)(x+10)=0

x-7=0

x+10=0

x=7

x=-10

AB=x+5

AB=12

AB=-5

BC=x-2

BC=5

BC=-12

Area of ABC = 30cm2

<u>Perimeter of ABC = AB+BC+</u><u>AC</u>

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8 0

2 years ago