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Lelu [443]
3 years ago
9

Name the acute angles in this figure. Choose all that apply.

Mathematics
2 answers:
Irina18 [472]3 years ago
4 0

Answer:

HEJ

DEH

JEK

KEF

KatRina [158]3 years ago
4 0

Answer:

HEJ

DEH

JEK

KEF

i think

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The expression on the left side of an equation is show below
max2010maxim [7]

Answer:

−4(x−2)+5x

Distribute:

=(−4)(x)+(−4)(−2)+5x

=−4x+8+5x

Combine Like Terms:

=−4x+8+5x

=(−4x+5x)+(8)

=x+8

8 0
3 years ago
Help me. The last person who answered this question just asked me for personal info.... so please just answer the question...
Lelechka [254]

Answer:

Step-by-step explanation:

so the least common denominator is 12, so:

multiply 3/4ab by three, which equals: 9/12ab

9/12ab-5/12ab = 4/12ab, or 1/3ab

3 0
3 years ago
3. What are the coordinates of the points of tangency of the two tangent lines through the point (1,1) each tangent to the circl
VashaNatasha [74]

Answer:y+x=2    

Step-by-step explanation:

Given

equation of circle x^2+y^2=1

Equation of tangent passing through (1,1)

Slope of tangent is given by differentiating equation of circle

2x+2y\frac{\mathrm{d} y}{\mathrm{d} x}=0

\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{-x}{y}

at (x,y)=(1,1)

\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{-1}{1}

Equation of line with slope

m=\frac{y-y_0}{x-x_0}

-1=\frac{y-1}{x-1}

y+x=2    

7 0
3 years ago
What number is 4 times as many as 25
Oduvanchick [21]
This is a standard relationship/systems of equations question.  Here is how you attack it.  Firstly, set up equations to represent the relationships. Ed = 4*Kim That shows that Ed has four times as many pins as Kim.  Next, we see that the two have 25 together.  So: Ed + Kim = 25 Now we have our two equations.  In order to solve, we need to get one of the equations down to one variable.  We can achieve this via substitution.  The first equation tells us that we can substitute 4*Kim for Ed (in the second equation).  So, let's do just that: 4*Kim + Kim = 255*Kim = 25Kim = 5 Using the first equation again, we can solve for Ed: Ed = 4*KimEd = 4*(5)<span>Ed = 20</span>
6 0
3 years ago
Read 2 more answers
ASAP plz answers just
faust18 [17]

Answer:

<em>(a) x(x+2)  (b) 2x(x-3)  (c) 5x(3-2x^2)  (d) 3x^2(3+x)</em>

Step-by-step explanation:

For each expression, <u>we need to factor out the GCF(Greatest common factor)</u>

a)   x^2+2x

Here, the GCF is  x. So, we will get.....

x^2+2x\\ \\ =x(\frac{x^2}{x}+ \frac{2x}{x}) \\ \\ =x(x+2)

b)   2x^2-6x

Here, the GCF is  2x. So, we will get......

2x^2-6x\\ \\ =2x(\frac{2x^2}{2x}- \frac{6x}{2x}) \\ \\ =2x(x-3)

c)   15x-10x^3

Here, the GCF is  5x. So, we will get.......

15x-10x^3\\ \\ =5x(\frac{15x}{5x}- \frac{10x^3}{5x}) \\ \\ =5x(3-2x^2)

d)   9x^2+3x^3

Here, the GCF is  3x^2. So, we will get.......

9x^2+3x^3\\ \\ =3x^2(\frac{9x^2}{3x^2}+ \frac{3x^3}{3x^2}) \\ \\ =3x^2(3+x)

8 0
4 years ago
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