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3 years ago

15

There are 9 gallons of paint for the students to use to paint the fence outside of the schoolyard. Each student has a bucket tha

t holds 1/3 gallon. How many buckets does the 9 gallons of paint fill?

1 answer:

Vera_Pavlovna [14]3 years ago

6 0

Answer:

27 buckets.

Step-by-step explanation:

If we multiply the 9 gallons of paint by the denominator of the number of gallons that fit into one of the buckets we can discover the answer to the question.

Brainliest please.

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Write the equation of the line that passes through the points (1,6) and (3, -4)

gavmur [86]

Answer:

A. y = -5x + 11

Step-by-step explanation:

The general form of the equation of a line is given as

y - y1 = m (x - x1)

where m is the slope and x1, y1 are the coordinates of a point on the line.

m = (y2 - y1)/(x2 - x1)

Given the points (1,6) and (3, -4)

m = (-4-6)/(3-1)

=-10/2

= -5

The equation of the line will be

y - 6 = -5(x -1)

y - 6 = -5x + 5

Add 6 to both side

y = -5x + 5 + 6

y = -5x + 11

Option A

6 0

3 years ago

urgent!! hal earns $5 doing chores for his parents. he also earns $10 a week for each dog, d, he walks.

zhannawk [14.2K]

Answer:

5+10d=x The dogs he walks are the ind variable and the total money he earns is the dep variable

Step-by-step explanation:

If he earns five dollars a week then that is a confirmed amount which means it’s just $5. Then for every dog he walks that’s $10 so if he walks 0 dogs then he gets $0.

The dogs he walks is ind because this variable is the variable that changes and effects the total whereas, the dep is the total because that’s what changes depending on the ind variable

6 0

3 years ago

How much times can 3 go into 78

Sedbober [7]

Answer:

26

Step-by-step explanation:

26 times

4 0

2 years ago

Read 2 more answers

Find the value of x.

VMariaS [17]

$\huge{ \bold{ \bigstar \: pythagoras \bigstar}}$

Pythagoras :

${10}^{2} = {x}^{2} + {x}^{2}$

$100 = 2{x}^{2}$

$100 \div 2 = {x}^{2}$

$50 = {x}^{2}$

$x = \sqrt{50}$

$x = \sqrt{25 \times 2}$

$\red{x = 5 \sqrt{2} }$

3 0

3 years ago

Read 2 more answers

Solve the initial value problem

tigry1 [53]

$9(t+1)\dfrac{\mathrm dy}{\mathrm dt}-7y=14t\implies\dfrac{\mathrm dy}{\mathrm dt}-\dfrac7{9(t+1)}y=\dfrac{14t}{9(t+1)}$

Look for an integrating factor $\mu(t)$ :

$\ln\mu=\displaystyle-\frac79\int\frac{\mathrm dt}{t+1}=-\frac79\ln(t+1)\implies\mu=(t+1)^{-7/9}$

Multiply both sides by $\mu$ :

$(t+1)^{-7/9}\dfrac{\mathrm dy}{\mathrm dt}-\dfrac79(t+1)^{-16/9}y=\dfrac{14}9t(t+1)^{-16/9}$

Condense the left side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[(t+1)^{-7/9}y\right]=\dfrac{14}9t(t+1)^{-16/9}$

Integrate both sides:

$(t+1)^{-7/9}y=\displaystyle\frac{14}9\int t(t+1)^{-16/9}\,\mathrm dt$

For the integral on the right, substitute

$u=t+1\implies t=u-1\implies\mathrm dt=\mathrm du$

$\displaystyle\int t(t+1)^{-16/9}\,\mathrm dt=\int(u-1)u^{-16/9}\,\mathrm du$

$\displaystyle=\int\left(u^{-7/9}-u^{-16/9}\right)\,\mathrm du=\frac92u^{2/9}+\frac97u^{-7/9}+C$

$\implies(t+1)^{-7/9}y=\dfrac{14}9\left(\dfrac92(t+1)^{2/9}+\dfrac97(t+1)^{-7/9}+C\right)$

$\implies(t+1)^{-7/9}y=7(t+1)^{2/9}+2(t+1)^{-7/9}+C$

$\implies y=7(t+1)+2+C(t+1)^{7/9}=7t+9+C(t+1)^{7/9}$

Given that $y(0)=12$ , we get

$12=9+C\implies C=3$

$\implies\boxed{y(t)=7t+9+3(t+1)^{7/9}}$

6 0

3 years ago