Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
3142 feet
Step-by-step explanation:
first, find the circumference of the wheel.
approx 75.4
every one rotation you travel approximately 75.4 inches
75.4 x 500 =37,700
37,700/12 = feet traveled
3141.6... feet
rounded = 3142
Sketch the points (0,5,2),(4,0,-1),(2,4,6) and(1,-1,2) o a single set of coordinate axes?
nordsb [41]
Explanation:
As points have three coordinates i.e. x, y and z hence the sketch of the given four points is drawn in 3D shape and for that picture is attached here with this answer.
Points are given in the format as below
(value of x-coordinate , value of y-coordinate , value of z-coordinate)
In the attachment:
Point A = (0,5,2) (in blue color)
Point B = (4,0,-1) (in purple color)
Point C = (2,4,6) (in orange color)
Point D = (1,-1,2) (in black color)
Answer:
a = 60
Step-by-step explanation:
4 + 6 = 10
6 = a/10
10*6 = 60
6 = 60/4+6
Hope this helps!
