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3 years ago

Quadrilateral ABCD is inscribed in this circle.

Mathematics

2 answers:

Kaylis [27]3 years ago

4 0

Answer:

∠B=132°

Step-by-step explanation:

It is given that Quadrilateral ABCD is inscribed in this circle and we know that the sum of the opposite angles of the quadrilateral inscribed in the circle equals 180°.

Therefore, ∠D+∠B=180°

⇒ $x+(3x-12)=180$

⇒ $4x=180+12$

⇒ $4x=192^{\circ}$

⇒ $x=48^{\circ}$

Thus, the measure of ∠B is= $3x-12=3(48)-12=144-12=132^{\circ}$

fgiga [73]3 years ago

3 0

Assuming the sum of the opposite angle would be 180. We can easily calculate for x and ultimately solve for the angle of B. We do as follows

B + D = 180
3x-12 + x = 180
4x - 12 = 180
4x = 192
x = 48 degrees

Therefore angle B would have a measurement of 132 degrees. Hope this helps.

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​ Quadrilateral ABCD ​ is inscribed in this circle.

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