Answer:
Part a) The approximate years were 1998 and 2008
Part b) The graph in the attached figure
Step-by-step explanation:
Part a) we have
For
Solve the quadratic equation
we know that
The formula to solve a quadratic equation of the form is equal to
in this problem we have
so
substitute in the formula
therefore
The approximate years are
1997+11=2008
1997+1=1998
Part b)
Using a graphing tool
we have
The solution of the system of equations is the intersection point both graphs
The intersection point are (0.99,80) and (11.23,80)
see the attached figure
therefore
The solution part a) is correct
if you wanna solve for m you have get m by him self.
m-n = 5
m-n+n = 5+n
m = 5+ n
there is your answer. hope it is heplful
Answer:
c) FJ and GH
Step-by-step explanation:
Answer:
Therefore, Δx=5/n, when have n intervals.
Step-by-step explanation:
From exercise we have interval [0,5]. So the length of the given interval is 5-0=5. Since all intervals [x0,x1],[x1,x2],…,[xn−1,xn] are equal in width.
We know that their width is Δx. We conclude that width of each subinterval Δx in terms of the number of subintervals n is equal 5/n.
Therefore, Δx=5/n, when have n intervals.