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Eddi Din [679]
3 years ago
6

Given cos(angle) = -5/13 where the terminal arm of angle lies in quadrant 2, evaluate each trigonometric expression

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer the answer is 76.6

Step-by-step explanation:

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Write an equation of the line that is parallel to -x + y = 5 and passes through the point (2,-5).
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Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

so convert the equation -x + y = 5 into slope intercept form by adding x to both sides

(-x + x) + y = 5 + x

0 + y = 5 + x

y = 5 + x

To match the slope intercept formula switch the x and 5 around

y = x + 5

If lines are parallel then they have the same slope (m) but they have different b

This means that the slope of the line will be 1 (in front of the x is an invisible 1 which would be m)

This is what we have so far...

y =  x + b

Now we must find b

To do that you must plug in the point the line goes through in the x and y of the equation.

(2, -5)

-5 = 1(2) + b

-5 = 2 + b

-7 = b

y = x + (-7)

y = x - 7

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Solve: 7 + 5 + 22 × 12 − 7 =
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By the order of operations, you first do the multiplication, then you can do the addition and subtraction

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