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Eddi Din [679]
2 years ago
6

Given cos(angle) = -5/13 where the terminal arm of angle lies in quadrant 2, evaluate each trigonometric expression

Mathematics
1 answer:
Mrrafil [7]2 years ago
3 0

Answer the answer is 76.6

Step-by-step explanation:

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The ratio of boys to girl in a certain class is 4:7. if there are 33 students in the class, how many of them are girls.
Elden [556K]
Your answer is that 21 are girls
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3 years ago
Find the diameter of a circle whose circumference is 74cm
jenyasd209 [6]
  • <em>Answer:</em>

<em>≈ 24 cm</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>c = 2πr  } => c = πd => d = c/π</em>

<em>2r = d</em>

<em>replace c ; π</em>

<em>π  =3.14</em>

<em>d = 74cm/3.14</em>

<em>= 23.5668</em>

<em>≈ 24 cm</em>

<em>Good luck !</em>

4 0
3 years ago
What is the 10th of a quarter of 1600
mihalych1998 [28]

Answer:

40

Step-by-step explanation:

A quarter of 1600 is 400. A tenth of that is 40.

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4 0
2 years ago
Read 2 more answers
Louisa states that the solution to the equation One-fourth x minus 3 = StartFraction 3 Over 8 EndFraction x + 4 is x = 56. She v
Gnom [1K]

Answer:

A

Step-by-step explanation:

The answer is A

6 0
3 years ago
Read 2 more answers
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
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