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kobusy [5.1K]
3 years ago
11

This table represents a quadratic function.

Mathematics
1 answer:
notsponge [240]3 years ago
4 0

Answer:

I think 1/2 is the ans

Step-by-step explanation:

quadratic function equation

would help

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What expression has a negative value?<br>7+3(-4)(2)<br>-2[12/(-3)]<br>(15-7)-(9/3)<br>-5[7+(-14)]-30
Soloha48 [4]

Answer:

7+3(-4)(2)= -17

Step-by-step explanation:

7+3(-4)(2)

(-4)*2=-8

∴ 7+3(-8)= 7-24

= -17

8 0
3 years ago
1. What is distributive property?
Ulleksa [173]
1..The distributive property is when you take the number and multiply it to the numbers in the parentheses

2.You must use the distributive property because it helps simplify difficult problems and breaks the problem down into a simpler version

3. To solve a multi step equations with parentheses you must use the addition property subtraction property distributive property in multiplication property if all are needed
7 0
4 years ago
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mojhsa [17]

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Step-by-step explanation:

5 0
3 years ago
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What is the value of p? 13^2=p Iready
pashok25 [27]

Answer:

I believe the answer is p=169?

Step-by-step explanation:

13^2 is 13×13 which equals 169

8 0
3 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
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