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EastWind [94]
3 years ago
12

What is the value of p? 13^2=p Iready

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0

Answer:

I believe the answer is p=169?

Step-by-step explanation:

13^2 is 13×13 which equals 169

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A designer is adding a pendant to a jewelry collection. The shape of the pendent can be defined by the equation
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Rewrite the perimeter formula, P = 2/ + 2w, to solve for the length, I, and then
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P = 2l + 2w

Subtract both sides by 2w

P - 2w = 2l

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3 0
3 years ago
Afla un numar,stiind ca: a)jumatatea treimii lui este 25; b)sfertul jumatatii lui este 48; c)treimea sfertului sau,marita cu 17
aalyn [17]

Answer:

(a) 150

(b) 384

(c)  84

(d) 261

(e ) 480

Step-by-step explanation:

(a)

Let 'a' be a number such that  the half of his third is 25; i.e.

\dfrac{1}{2}\times(\dfrac{1}{3}a)=25\\\\\dfrca{1}{2\times3}a=25\\\\\dfrac{1}{6}\times a=25\\\\a=25\times6\\\\a=150    

Hence, the number is 150.

(b)

Let 'b' be  the number such that the quarter of his half is 48 i.e.

\dfrac{1}{4}(\dfrac{1}{2}b)=48\\\\\dfrac{1}{8}b=48\\\\b=48\times8\\\\b=384

Hence the number is 384.

(c)

Let 'c' be the number such that the third quarter or, increased by 17 is 80.

\dfrac{3}{4}c+17=80\\\\\dfrac{3}{4}c=80-17\\\\\dfrac{3}{4}c=63\\\\c=\dfrac{63\times4}{3}\\\\c=\dfrac{252}{3}\\\\c=84

Hence, the number is 84.

(d)

Let 'd'  be the number such that its triplet, reduced by 28 is 755

3d-28=755\\\\3d=755+28=783\\\\d=\dfrac{783}{3}\\\\d=261

Hence the number is 261.

(e  

Let 'e' be the number such that double his third, increased by 80 is 400.

\\2\dfrac{1}{3}e+80=400\\\\\dfrac{2}{3}e=400-80=320\\\\e=\dfrac{320\times 3}{2}\\\\e=\dfrac{960}{2}\\\\e=480

Hence, the value of the number is 480.


4 0
3 years ago
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