To test upper h 0 : mu equals 72 versus upper h 1 : mu less than 72, a simple random sample of size nequals20 is obtained from
a population that is known to be normally distributed, and the sample standard deviation is found to be 6. complete parts (a) and (b) below.
1 answer:
We solve using equation
![\beta \sqrt{x} \sqrt[n]{x} \lim_{n \to \infty} a_n \alpha](https://tex.z-dn.net/?f=%20%5Cbeta%20%20%20%5Csqrt%7Bx%7D%20%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%5Calpha%20)
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Point A and B of what? Plz show a number line or graph or table or something.
Answer:9
Step-by-step explanation: 31-4=27
27÷3=9
74-34=20 so then y=20 because 20*2+34=74
IN other words
74-34=20
Step-by-step explanation:
a−(6a−(5a−8))
a-(6a-5a+8)
a-6a+5a-8
6a-6a-8
0-8
=-8
so the answer doesn't depend on a
Answer:
7
Step-by-step explanation:7