I think it’s irrational, because the 5 is repeating
Answer:
P(x)= x ^4-3x^3+x^2-4
Step-by-step explanation:
Given data
R(x) = 2x ^4-3x^3+2x-1
c(x)=x^4-x^2+2x+3
We know that
P(x)=R(x)-C(x)
Hence
P(x)= 2x ^4-3x^3+2x-1-(x^4-x^2+2x+3)
open bracket
P(x)= 2x ^4-3x^3+2x-1-x^4+x^2-2x-3
Collect like terms
P(x)= 2x ^4-x^4-3x^3+x^2-2x+2x-3-1
P(x)= x ^4-3x^3+x^2-4
Its pretty simple
9x-7y = 22
x + 3y = -24
(9x-7y = 22)
-9(x + 3y = -24)
= -9x -27y = 216
+ 9x-7y = 22
= -34y = 238
= / -34 = 238/-34
y = -7
now plug -7 in one of the equation
x + 3(-7) = -24
x -21 = -24
+21. +21
x = -3
so answer is x = -3 and y = -7
Answer:
A, y = 3x/2 - 12
Step-by-step explanation:
Use the equation y = mx + b.
m = 3/2
b = -12
y = 3x/2 - 12
Answer:
Either, (9+√69)/6 or (9-√69)/6
Step wise:
3x²-9x+1=0-------------------(i)
comparing equation onw with (ax²+bx+c=0), we get,
a=3, b=-9, c=1
now,
using Quadratic Formula,
(-b±√b²-4ac)/2a=x
{-(-9)±√(-9)²-4.3.1}/2.3=x
(9±√81-12)/6=x
(9±√69)/6=x
Taking +(ve) sign Taking -(ve) sign
(9+√69)/6=0 (9-√69)/6=0
∴(9+√69)/6=0 ∴(9-√69)/6=0
[∵They cannot be further solved]