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4 years ago

Ayo someone pls respond , I’ll give that brain god prize thing to you

Mathematics

1 answer:

eduard4 years ago

7 0

Answer: Choice A

Explanation:

$\frac{h}{6}$ = quotient of h and 6

$\frac{h}{6}+7.8$ = 7.8 more than the quotient of h and 6

$\frac{h}{6}+7.8 = w$

The "is" often refers to "equals" in math translation problems like this.

Another example "h is 10" means "h = 10".

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Select all the correct answers.

ohaa [14]

Answer:

Lines 3 and 4

Step-by-step explanation:

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8 0

3 years ago

Expand and simplify 5(2x-1)-2(3x+2)

kupik [55]

Answer:

4x - 9

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Terms/Coefficients/Degrees

Step-by-step explanation:

Step 1: Define

5(2x - 1) - 2(3x + 2)

Step 2: Solve for x

Distribute: 10x - 5 - 6x - 4
Combine like terms (x): 4x - 5 - 4
Combine like terms (Z): 4x - 9

6 0

3 years ago

How do you simplify numbers with exponents

tensa zangetsu [6.8K]

You write it out then you’ll get the exponent

7 0

3 years ago

Sin(A+B) sin(A-B) /sin^A Cos^B=1-cot^A Tan^B

telo118 [61]

In order to prove

$\dfrac{\sin(x+y)\sin(x-y)}{\sin^2(x)\cos^2(x)}=1-\cot^2(x)\tan^2(y)$

Let's write both sides in terms of $\sin(x),\ \sin^2(x),\ \cos(x),\ \cos^2(x)$ only.

Let's start with the left hand side: we can use the formula for sum and subtraction of the sine to write

$\sin(x+y)=\cos(y)\sin(x)+\cos(x)\sin(y)$

and

$\sin(x-y)=\cos(y)\sin(x)-\cos(x)\sin(y)$

So, their multiplication is

$\sin(x+y)\sin(x-y)=(\cos(y)\sin(x))^2-(\cos(x)\sin(y))^2\\=\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)$

So, the left hand side simplifies to

$\dfrac{\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now, on with the right hand side. We have

$1-\cot^2(x)\tan^2(y)=1-\dfrac{\cos^2(x)}{\sin^2(x)}\cdot\dfrac{\sin^2(y)}{\cos^2(y)} = 1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now simply make this expression one fraction:

$1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}=\dfrac{\sin^2(x)\cos^2(y)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

And as you can see, the two sides are equal.

6 0

4 years ago

PLEASE HELP ASAP!!!!!!!!!!!! 50% of my grade NO FAKE ANSWERS!!!!!!!!!!!!

photoshop1234 [79]

i can confirm this answer is not indeed fake

7 0

3 years ago