When do we use = and when do we use ~

1 answer:

4 0

When we use this = it means it is the exact
answer
When we use ≈ it means it is an estimated answer and not the exact answer Example 12.4684729572974729758328 ≈ 12

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How do you solve √125÷√5

nordsb [41]

$\bf \sqrt{125}\div \sqrt{5}\implies \cfrac{\sqrt{125}}{\sqrt{5}}\qquad \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^2\cdot 5 \end{cases}\implies \cfrac{\sqrt{5^2\cdot 5}}{\sqrt{5}} \\\\\\ \cfrac{5~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 5$

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3 years ago

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I am Lyosha [343]

404 in. squared is the answer.

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4 years ago

Show that if x, y, z are integers such that x^3+5y^3 = 25z^3, then x = y = 0.

Gre4nikov [31]

Answer:

3125*k^9 + y^3 is an integer my closure property.

but 5^(1/3) is not an integer, which forces z to be irrational.

Note that there is no way an integer value can rationalize 5^(1/3)

Step-by-step explanation:

x^3 = 25z^3 - 5y^3

x^3 = 5 ( 5z^3 - y^3)

x = (5 ( 5z^3 - y^3) )^(1/3) must be an integer

= 5^(1/3) * (5z^3 - y^3)^(1/3)

Then (5z^3 - y^3)^(1/3) = 25*k^3 for some integer k

5z^3 - y^3 = 15625*k^9

5z^3 = 15625*k^9 + y^3

z^3 = 3125*k^9 + (1/5)*y^3

z = ( 3125*k^9 + (1/5)*y^3 )^ ( 1/3)

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3 years ago

matrenka [14]

Answer:

C 470

Step-by-step explanation:

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3 years ago

Lines that are parallel have the same slope or else no slope.

hammer [34]

This is true, if that's what your looking for. because theyre parallel they have to same slope.

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3 years ago