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Eddi Din [679]
3 years ago
8

How do you solve √125÷√5​

Mathematics
1 answer:
nordsb [41]3 years ago
8 0

\bf \sqrt{125}\div \sqrt{5}\implies \cfrac{\sqrt{125}}{\sqrt{5}}\qquad \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^2\cdot 5 \end{cases}\implies \cfrac{\sqrt{5^2\cdot 5}}{\sqrt{5}} \\\\\\ \cfrac{5~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 5

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F ( x ) = 7 x + 2
y = 7 x + 2
- 7 x = - y + 2  /*(-1)
7 x = y - 2   / : 7
x = y/7 - 2/7 = ( y - 2 ) / 7
The inverse of the function is:
f^(-1) ( x ) = ( x - 2 ) /7 

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3 years ago
Name The postulate or theorem you can use to prove the triangles congruent
Zielflug [23.3K]
The answer is HL. HL is a theorem stating that if the hypotenuse and one leg are congruent to another pair of hypotenuse and leg then the triangles themselves are congruent. Hope this helps. 
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3 years ago
potatoes - Samples: Assume the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standa
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In some gymnastics meets, the score given to a gymnast is the mean of the judges’ scores after the highest and lowest scores h
Allisa [31]

Using the median concept, the correct statement is given as follows:

Her median score does not change.

<h3>What is the median of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile, also called the middle value the data-set, not being affected by outliers.

For this problem, the data-set is given as follows:

7.50, 7.50, 7.75, 7.75, 8.00, 8.00, 8.00, 10.00.

There are 8 scores, hence the median is the <u>mean of the 4th and the 5th</u> scores, as follows:

(7.75 + 8)/2 = 7.875.

Removing the extreme values, the data-set will be given by:

7.50, 7.75, 7.75, 8.00, 8.00, 8.00.

Then it has 6 scores, hence the median is the <u>mean of the 3th and the 4th</u> scores, as follows:

(7.75 + 8)/2 = 7.875.

Same median, hence the correct option is:

Her median score does not change.

More can be learned about the median of a data-set at brainly.com/question/23923146

#SPJ1

7 0
2 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
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