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Eddi Din [679]
3 years ago
8

How do you solve √125÷√5​

Mathematics
1 answer:
nordsb [41]3 years ago
8 0

\bf \sqrt{125}\div \sqrt{5}\implies \cfrac{\sqrt{125}}{\sqrt{5}}\qquad \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^2\cdot 5 \end{cases}\implies \cfrac{\sqrt{5^2\cdot 5}}{\sqrt{5}} \\\\\\ \cfrac{5~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 5

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What is the range for y=x^2-7x-8 ?
gtnhenbr [62]

Answer:

[-20.25;+∞).

Step-by-step explanation:

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2) y₀=-20.25 means, the value -20.25 is minimum of the range, the maximum →+∞;

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7 0
2 years ago
Salem High School's winter sports teams WON 72% of their games last season. If the teams played 50 games, how many games did the
Dmitriy789 [7]

Answer

Find out the how many games did the teams lose .

To prove

Formula

Percentage = \frac{Part\ value\times 100}{Total\ values}

As given

Salem High School's winter sports teams WON 72% of their games last season.

If the teams played 50 games .

Percentage = 72%

Total value = 50

Put in the formula

72 = \frac{Number\ of\ games\ win\times 100}{50}

Number\ of\ games\ win = \frac{72\times 50}{100}

Number of games win = 36

Number of  games teams loses = Total number of games - number of games win

                                                          = 50 - 36

                                                          = 14

Therefore the number of games  team loses are 14 .



5 0
3 years ago
Help please! No rush, I'll give brainliest for best answer​
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9514 1404 393

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  A

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