Answer:
- plane: 550 mph
- wind: 50 mph
Step-by-step explanation:
If p and w represent the speeds of the plane and wind, respectively, the speed into the wind is ...
p - w = (3000 mi)/(6 h) = 500 mi/h
And, the speed with the wind is ...
p + w = (3000 mi)/(5 h) = 600 mi/h
Adding these two equations gives us ...
2p = 1100 mi/h
p = 550 mi/h . . . . . . . divide by 2
Then the wind speed is ...
w = 600 mi/h - p = (600 -550) mi/h
w = 50 mi/h
The rate of the plane in still air is 550 mi/h; the rate of the wind is 50 mi/h.
What grade are u in so i can try to help u
(76.4)(0.32)(R - 112) + (0.35)(20R + 435) = 54
24.448(R - 112) + 7R + 152.25 = 54
24.448R - 2738.176 + 7R + 152.25 = 54
31.448R - 2585.926 = 54
31.448R = 54 + 2585.926
31.448R = 2639.926
R = 2639.926/31.448
R = 83.9457
Answer:
0.6
Step-by-step explanation:
12/20 = 6/10 = 0.6
An <em>angle bisector</em> is a <u>straight line</u> that <em>divides</em> a given <u>angle</u> into two <u>equal</u> measures. Thus the measure of <u>angle</u> FBC is
.
A <u>line</u> that <em>divides</em> a given measure of angle into <em>two equal</em> measures is referred to as an <em>angle bisector</em>. This makes the <em>two angles</em> produced by the <u>bisector</u> to be <u>congruent</u>.
Thus from the given question, we have;
<ABD + <DBC = < ABC (<u>addition</u> property of a <em>bisected angle</em>)
<ABE + <EBD = <ABD (<u>addition</u> property of a bisected angle)
<EBF + <FBD = <EBD (<u>addition</u> property of a <em>bisected angle</em>)
Given that angle ABE =
, thus;
<ABE = <EBD = 
Then,
<EBF + <FBD = 
<EBF = <FBD = 
Such that;
<FBC = <FBD + <DBC
=
+ 2<ABE
=
+ 
<FBC = 
Therefore, the <em>measure</em> of <u>angle</u> FBC is
.
For more clarifications on bisection of a given angle, visit: brainly.com/question/17247176
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