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Alenkasestr [34]
3 years ago
11

I need help with this please help me thank you!

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

Step-by-step explanation:

since AC=BC and <ace=<bce and share CD, side-angle-side

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A laptop computer is purchased for 3100. Each year, its value is 75% of its value the year before. After how many years will the
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Answer:7 to 9? Years

Step-by-step explanation: I’m not sure but if you got a couple trys try to do it.

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What is the sum of the first five terms of a geometric series with a1 =20 and r =1/4?
drek231 [11]
The sum of the first n terms in a geometric sequence given the first term (a1) and the common ratio (r) is calculated through the equation,

                            <span>Sn </span>= (<span><span><span>a1</span>(1−<span>r^n</span>) / (</span><span>1−r)

Substituting the known terms,
                           Sn = (20)(1 - (1/4)^4)) / (1 - 1/4)
                           Sn = 26.5625

Thus, the sum of the first four terms is 26.5625. </span></span>
5 0
3 years ago
Answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr pls
Gelneren [198K]

Answer:

the answer is b.11

Step-by-step explanation:

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3 years ago
Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t
Amanda [17]

Answer:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

df = n-1= 22-1=21

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

\bar X=33.9 represent the sample mean

s=4.1 represent the sample standard deviation

n=22 sample size  

\mu_o =26 represent the value that we want to test

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:  

Null hypothesis:\mu \geq 36  

Alternative hypothesis:\mu < 36  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

Now we can calculate the critical value but first we need to find the degreed of freedom:

df = n-1= 22-1=21

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0
3 years ago
Find the solution of y = 6x + 1 for x = 5.
Fudgin [204]
The solution is D.
By plugging the x value, 5, into the equation:
6*5=30
30+1=31
y=31
the x value is 5 and the y value is 31
(5, 31)
hope that helps!
7 0
3 years ago
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