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2 years ago

CAN SOMEONE PLEASE HELP ME?

Mathematics

1 answer:

Novay_Z [31]2 years ago

4 0

108 because 2 is a vertical angle and VAs are congruent. 3 is a correspomding angle, and theyre also congruent

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How many white marbles are there?

vitfil [10]

I believe the answer is 6 white marbles. how i figured that out was i made an equation. i took the variable Y (for the yellow marbles) times 2 minus 6 equals 18. you then add 6 to the other side of the equal sign to cancel out the 6. you then have y(2)=24. you divide y and 24 by 2. you get 12 yellow marbles. next step is to take 18 - 12. you are left with 6 white marbles. hope this helps!

7 0

2 years ago

A candle maker has 4 1/2 pounds of clear wax. He wants to cut the wax into pieces that are 2/3 pound each. How many 2/3 pound pi

prisoha [69]

Answer:

a) 10 pieces of 2/3 pound can be made.

b) 0.54 pounds of wax is left over.

Step-by-step explanation:

Total amount of clear wax available = $4\frac{1}{2} = \frac{9}{2}$ pounds

So, the maker has in total 4.5 pounds of wax

Now, The weight of each piece = $\frac{2}{3} = 0.66$ pounds

To find the number of pieces that can be made out of 4.5 pounds of wax,

let that number = n

So, $n = \frac{\textrm{Total weight of the clear wax}}{\textrm{Weight of each wax}}$

or, n = $n = \frac{4.5}{0.66} = 6.81$

So, nearly 6 pieces can be made completely out of the clear wax

Left over amount of wax = Total weight - Weights of the pieces made

= 4.5- 6(0.66)

= 0.54 pounds

Hence, 0.54 pounds of wax is left over

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3 years ago

A population of caribou in a forest grows at a rate of 2% every year. If there are currently 273 caribou, which function represe

Feliz [49]

Answer:

Step-by-step explanation:

C (t)= 273 (0.02)t

6 0

3 years ago

A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled.

kykrilka [37]

Answer:

1/6

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2 years ago

Express the negations of each of these statements so that all negation symbols immediately precede predicates. a) ∀x∃y∀zT(x, y,

Gnesinka [82]

Answer:

a) ∀x∃y ¬∀zT(x, y, z)

∀x∃y ∃z ¬T(x, y, z)

b) ∀x¬[∃y (P(x, y) ∨ Q(x, y))]

∀x∀y ¬ [P(x, y) ∨ Q(x, y)]

∀x∀y [¬P(x, y) ^ ¬Q(x, y)]

c) ∀x ¬∃y (P(x, y) ^ ∃zR(x, y, z))

∀x ∀y ¬(P(x, y) ^ ∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ¬∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ∀z¬R(x, y, z))

d) ∀x¬∃y (P(x, y) → Q(x, y))

∀x∀y ¬(P(x, y) → Q(x, y))

∀x∀y (¬P(x, y) ^ Q(x, y))

3 0

2 years ago

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