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kondaur [170]
4 years ago
15

one sixth of the party guests were Wildcats fan the rest were knight fan. what fraction were knight fans?​

Mathematics
2 answers:
xxMikexx [17]4 years ago
4 0

Answer:

5/6

Step-by-step explanation:

Subtract one sixth from 1 whole to get 5/6

MakcuM [25]4 years ago
3 0

Answer:

5/6 were knight fans.

Step-by-step explanation:

The problem explained that 1/6 of the party guests were Wildcats fans this means that 6 is the whole. if one sixth is if you are to subtract the numerators given. we know the whole is 6 and 1/6 of the party guests were Wildcats fans so if you were to subtract 6/6 by 1/6 your answer would be 5 out of 6 Knight fans.

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2 years ago
Expand and simplify (x+5)(x-2)
salantis [7]

Answer:

{x}^{2} - x - 12 = (x + 3)(x - 4)

{x}^{2} + 3x + 2 = (x + 2)(x + 1)

{x}^{2} + 3x - 10 = (x + 5)(x - 2)

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

{x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12

{x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2

{x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10

I am joyous to assist you anytime.

8 0
3 years ago
Determine whether the statements are True or False. Justify your answer with an explanation.
frez [133]

Problem 1

<h3>Answer: False</h3>

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Explanation:

The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.

So,

f(x) = x+1

f( g(x) ) = g(x) + 1 .... replace every x with g(x)

f( g(x) ) = 6x+1 ... plug in g(x) = 6x

(f o g)(x) = 6x+1

Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

g( f(x) ) = 6x+6

(g o f)(x) = 6x+6

This shows that (f o g)(x) = (g o f)(x)  is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

---------------------------------

Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

f(x) = 1/(x+2)

g(x) = -2

The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

7 0
3 years ago
Find the measure of angles A and B in the diagrams below.​
Karolina [17]

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3 years ago
Please help me with algebra part B and C. attachment below. Will mark as brainslist. 25 points.
miv72 [106K]

Answer:

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Now,

x_1=\dfrac{-b+\sqrt{D}}{2a}=\dfrac{-32+88}{2\cdot (-7)}=-4\\ \\x_2=\dfrac{-b-\sqrt{D}}{2a}=\dfrac{-32-88}{2\cdot (-7)}=\dfrac{60}{7}

Write the factored form:

-7x^2+32x+240=-7(x-(-4))\left(x-\dfrac{60}{7}\right)=(x+4)(-7x+60)

8 0
3 years ago
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