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Afina-wow [57]
3 years ago
10

HELP GEO QUESTION THX... GIVE ME EXPLANATION PLZZZZZ THXXXXX SOO MUCCHHHH

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

E is the midpoint of DA, and F is the midpoint of DB. This means EF is a midsegment of the triangle. It is half as long as AB, and EF is also parallel to AB.

When we extend EF to form segment EC, it is now twice as long compared to EF. So that shows EC is the same length as AB, in other words, EC = AB. Also, EC is parallel to AB. This works due to points E, F, and C being on the same line.

Since EC || AB, we know that angle EBA = angle BEC. These are alternate interior angles.

From the reflective property, we can say EB = EB

---------------

Using these three facts

  • EC = AB
  • angle EBA = angle BEC
  • EB = EB

to prove that triangle EBA is congruent to triangle BEC. The next step is to use CPCTC (corresponding parts of congruent triangles are congruent) to lead to

angle BEA = angle EBC

we can use the alternate interior angle theorem converse to conclude that EA is parallel to BC.

-----------------

In summary, we have proven:

  • EC is parallel to AB
  • EA is parallel to BC

By the definition of what it means to be a parallelogram, we have proven quadrilateral EABC is a parallelogram. In short, we've shown that the opposite sides are parallel.

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Answer: D

Step-by-step explanation:

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3 years ago
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The expression 20a + 13c is the cost (in dollars) for adults and students to enter a science center. Find the total cost for 4 a
lapo4ka [179]

Answer:

$392

Step-by-step explanation:

Given the expression :

Total cost = 20a + 13c

a = adult

c = student

The total cost for 4 adults and 24 students

a = 4 ; c = 24

Total cost :

20(4) + 13(24)

80 + 312

= $392

3 0
3 years ago
A student wants to use the property
Ratling [72]

Answer:

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6 0
3 years ago
Can anyone help me integrate :
worty [1.4K]
Rewrite the second factor in the numerator as

2x^2+6x+1=2(x+2)^2-2(x+2)-3

Then in the entire integrand, set x+2=\sqrt3\sec t, so that \mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt. The integral is then equivalent to

\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt

Note that by letting x+2=\sqrt3\sec t, we are enforcing an invertible substitution which would make it so that t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3} requires 0\le t or \dfrac\pi2. However, \tan t is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which \tan t>0 so that |\tan t|=\tan t. This allows us to write

=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt
=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt

We can show pretty easily that

\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C
\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C
\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C
\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C

which means the integral above becomes

=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C
=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C

Back-substituting to get this in terms of x is a bit of a nightmare, but you'll find that, since t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}, we get

\sec t=\dfrac{x+2}{\sqrt3}
\sec^2t=\dfrac{(x+2)^2}3
\tan t=\sqrt{\dfrac{x^2+4x+1}3}
\cot t=\sqrt{\dfrac3{x^2+4x+1}}
\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}
\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}

etc.
3 0
3 years ago
Consider the following data:
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Answer: x =6

Step-by-step explanation:

8 0
3 years ago
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