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Evgesh-ka [11]
3 years ago
6

Priscilla graphed function g, a transformation of the quadratic parent function f(x)=1/2f(x+2)-1 which statement is correct?

Mathematics
2 answers:
Serga [27]3 years ago
6 0

Answer:

Step-by-step explanation:

A.)Priscilla made a mistake when applying the horizontal shift.  That "x+2" indicates a horiz. shift to the LEFT, not to the right.

Brums [2.3K]3 years ago
4 0

Answer:

Option A.

Step-by-step explanation:

Priscilla graphed function g(x), a transformation of the quadratic parent function f (x) = \frac{1}{2} f ( x+2 ) - 1

(1) She graphed the vertical compression correctly

(2) Priscilla graphed the vertical shift of (-1) means 1 unit downwards on y-axis correctly.

(3) In the last she made a mistake because for f(x+2) the parent function should have been shifted left on x-axis by two units f (x) ⇒ f[ x- (-2)]

Therefore Option A will be the answer.

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
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The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
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