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Natali5045456 [20]
2 years ago
13

You have a box with dimensions 2 ft. x 4 ft. x 3 ft. a. If you want to wrap the box, what is the minimum amount of wrapping pape

r you need? b. If the paper cost $2.59 per square foot, what is the minimum cost?
Mathematics
1 answer:
shusha [124]2 years ago
5 0

Answer: A) 52 ft  B) $134.68

Step-by-step explanation:

First find the surface area by multiplying the dimensions together.

2 x 4 = 8

2 x 3 = 6

4 x 3 = 12

Then add them up and multiply by two because there are two of each side.

26 x 2 = 52

To find the cost, multiply 52 by $2.59 to get the price.

52 x $2.59 = $34.68

You might be interested in
Ms. Sacksteader owns a grocery store. She buys 272 pounds of potatoes for $99. She wants to sell them for twice as much. She mak
guajiro [1.7K]

Answer:she can sell 36 5-pound bags


Step-by-step explanation:

Take 272-90=182 then take 182÷5=36

6 0
2 years ago
The length of the minute hand is 150% of the length of the hour hand. In 1 hour, how much farther does the tip of the minute han
tatiyna

Answer:

17(pi)r/6

Step-by-step explanation:

Since neither hand length is known, you can have an answer in terms of one of the hands, but you cannot get just a number.

Let r = the length of the hour hand.

Then, the length of the minute hand is 150% of r = 1.5r.

The minute hand is the radius of the circle drawn by the tip of the minute hand. In 1 hour, the minute hand rotates one full revolution, so the tip of the minute hand moves the circumference of the circle drawn by the tip of the minute hand.

Now we find the circumference of the circle of the tip of the minute hand.

C = 2 * pi * r,

but the radius here is 1.5r, so we get

C_minute_hand =  2 * pi * (1.5)r

C_minute_hand = 3(pi)r

The hour hand rotates a full revolution in 12 hours, so it rotates 1/12 of a revolution in 1 hour. The radius is r.

C_hour_hand = 2 * pi * r * 1/12

C_hour_hand = (pi)r/6

The difference in how much each tip travels is

3(pi)r - (pi)r/6 = (pi)r(3 - 1/6) = 17(pi)r/6

5 0
2 years ago
The point (3, 6) is on the graph of y= 5f(2(x+3))-4 . Find the original point on the graph of y=f(x).
Sonja [21]

Answer:

<em>(12, 2)</em> is the original point on the graph of y=f(x).

Step-by-step explanation:

<u>Given:</u>

y= 5f(2(x+3))-4 has a point <em>(3, 6)</em> on its graph.

<u>To find:</u>

Original point on graph y=f(x) = ?.

<u>Solution:</u>

We are given that The point (3, 6) is on the graph of y= 5f(2(x+3))-4

If we put x = 3 and y = 6 in y= 5f(2(x+3))-4, it will satisfy the equation.

Let us the put the values and observe:

6= 5f(2(3+3))-4\\\Rightarrow 6= 5f(2(6))-4\\\Rightarrow 6= 5f(12)-4\\\Rightarrow 6+4=5f(12)\\\Rightarrow 5f(12)= 6+4\\\Rightarrow 5f(12)= 10\\\Rightarrow f(12)= \dfrac{10}{5}\\\Rightarrow f(12)= 2\\OR\\\Rightarrow 2=f(12)

Now, let us compare the above with the following:

y=f(x)

we get y = 2 and x = 12

So, the original point on graph of y=f(x) is <em>(12, 2).</em>

7 0
2 years ago
There is a bag filled with 5 blue, 2 red and 3 green marbles,
nikdorinn [45]

Answer:

0.62

Step-by-step explanation:

There are a total of 10 marbles in the bag.

P(blue and not blue) = 5/10 × 5/10 = 25/100

P(red and not red) = 2/10 × 8/10 = 16/100

P(green and not green) = 3/10 × 7/10 = 21/100

P = 25/100 + 16/100 + 21/100

P = 62/100

P = 0.62

Alternatively, you can calculate it this way:

P(both blue) = (5/10)² = 25/100

P(both red) = (2/10)² = 4/100

P(both green) = (3/10)² = 9/100

P = 1 − (25/100 + 4/10 + 9/100)

P = 1 − 38/100

P = 62/100

P = 0.62

5 0
2 years ago
During taylor's experiment, which piece of data would be qualitative?
Reptile [31]

There isn't any piece of data during Taylor's experiment which can be taken as  qualitative. Thus, correct choice is: Option D: None are qualitative.

<h3>What is qualitative data?</h3>

Qualitative data tells about the quality or characteristic. It is tough to express it numerically or not at all expressible numerically. They are usually catagorical.

In contrast, there is quantitative data which can be expressed numerically.

The problem is missing its option, which are:

  1. mass of the cars
  2. degree of the ramp incline
  3. time in seconds
  4. none are qualitative

Mass can be measured (in kgs, grams etc), degree of inclination can be measured (in radians, degree etc), time can be measured (in seconds, minutes etc).

Thus, there isn't any piece of data during Taylor's experiment which can be taken as  qualitative. Thus, correct choice is: Option D: None are qualitative.

Learn more about qualitative and quantitative data here:

brainly.com/question/12929865

5 0
2 years ago
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