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Natali5045456 [20]
3 years ago
13

You have a box with dimensions 2 ft. x 4 ft. x 3 ft. a. If you want to wrap the box, what is the minimum amount of wrapping pape

r you need? b. If the paper cost $2.59 per square foot, what is the minimum cost?
Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer: A) 52 ft  B) $134.68

Step-by-step explanation:

First find the surface area by multiplying the dimensions together.

2 x 4 = 8

2 x 3 = 6

4 x 3 = 12

Then add them up and multiply by two because there are two of each side.

26 x 2 = 52

To find the cost, multiply 52 by $2.59 to get the price.

52 x $2.59 = $34.68

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y= (\frac 1 4 )^x

A reflection about the x axis, about y=0, is the mapping (x',y')=(x,-y) so

y'= -y = - (\frac 1 4)^{x'}

A dilation of 2 is the mapping (x'',y'')=(2x', 2y')

So

x'=x''/2, y'=y''/2

y''/2= - (\frac 1 4)^{x''/2}

y'' =  - 2((\frac 1 4)^{1/2})^{x''}

y''= - 2(\frac 1 2)^{x''}

We can rewrite that without the primes and combine the powers of 2.

y =  - 2^{1-x}

Let's graph these and see if we're close,

Plot y= (1/4)^x, y= - (1/4)^{x}, y = - 2^{1-x}

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Step-by-step explanation:

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