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Gwar [14]
3 years ago
12

Rewrite the expressions in each pair so that they have the same base. c) (1 /2)^2x and (1/ 4)^x - 1

Mathematics
1 answer:
just olya [345]3 years ago
7 0
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
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Happy New Year from MrBillDoesMath!

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Proof by ASA congruence postulate. See below

Discussion:

  Fact 1 :     angle A = angle T             (given)

  Fact 2:    The angles on both sides of point X are equal as vertical angles

                 are equal.

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