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Gwar [14]
4 years ago
12

Rewrite the expressions in each pair so that they have the same base. c) (1 /2)^2x and (1/ 4)^x - 1

Mathematics
1 answer:
just olya [345]4 years ago
7 0
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
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10 divided by 2-(16 divided by 4) +14
ankoles [38]

Answer:

15

Step-by-step explanation:

okay so you gotta use pemdas (p = parentheses, e = exponents, m = multiplication, d = division, a = addition, s = subtraction), but for the multiplication/division and addition/subtraction parts, if  division or subtraction happens first then you must do it first rather than doing multiplication or addition first

10 / 2 -(16/4) + 14

10 / 2 -(4) + 14

5 - 4 + 14

1 + 14

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7 0
3 years ago
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GaryK [48]
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Then, we add the number obtained above and 180.
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ANSWER: 720
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3 years ago
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dalvyx [7]

Answer:

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Step-by-step explanation:

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5 0
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Svetradugi [14.3K]
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I hope this helps you :)
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