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Gwar [14]
4 years ago
12

Rewrite the expressions in each pair so that they have the same base. c) (1 /2)^2x and (1/ 4)^x - 1

Mathematics
1 answer:
just olya [345]4 years ago
7 0
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
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3 years ago
What is the solution of the system? Use the elimination method. 2x+y=20 6x?5y=12
Whitepunk [10]

Answer:

(22, - 24)

Step-by-step explanation:

Multiply the first equation by -5 to make the y's so you can add the up to zero.

-5(2x + y = 20)

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<u> 6x + 5y = 12  </u>

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3 0
4 years ago
Read 2 more answers
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zaharov [31]

Answer:

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Step-by-step explanation:

Given

N = -2F --- North Dakota

C = 1F --- Cheyenne, Wyoming

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From the given temperatures, we can conclude that:

C > N or N < C

Because

1 > -2 i.e. 1 is greater than -2

or

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C = 1F

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|C| = 1

By comparison:

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Because

2 > 1 i.e. 2 is greater than 1

or

1 < 2 i.e. 1 is less than 2

4 0
3 years ago
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Substitute in the values. y-(-4)=3(x-(-2))

Simplify the negative subtraction to addition. \boxed{y+4=3(x+2)}

8 0
3 years ago
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